Because they have aromas, compounds with a ring of resonance bonds are called

Choose the best classification of the reactions C6H12O6 (g) + 6O2 yields 6CO2 + 6H2O

marta [7]

Combustion reaction because it produces water and carbon dioxide

6 0

3 years ago

A major computer chip manufacturer has lost its supplier of silicon. Silicon is widely used in the semiconductor industry becaus

-BARSIC- [3]

We know, silicon is a natural semi-conductor, if manufacturer has lost its supplier then they can look for another element which is quite similar to silicon in electronic configuration.
We should go down the group, next element in 14th group is "Germanium" so we can use that for that purpose.

In short, Your Answer would be "Germanium"

Hope this helps!

6 0

3 years ago

(a) Calculate the wavelength of light in vacuum that has a frequency of 5.49 ✕ 1018 Hz. 0.0546 Correct: Your answer is correct.

vfiekz [6]

Answer:

a) Wavelength of the light in vacuum = (5.46 × 10⁻¹¹) m = 0.0546 nm

b) Wavelength of the light in diamond = (2.26 × 10⁻¹¹) m = 0.0226 nm

c) Energy of one photon in vacuum = (3.638 × 10⁻¹⁵) J = (2.271 × 10⁴) eV

d) No, the energy of the photon doesn't change when it is travelling inside diamond.

Explanation:

Wavelength (λ), frequency (f) and velocity of light (v) are related as thus

v = fλ

a) v = fλ

v = velocity of light in vacuum = (3.0 × 10⁸) m/s

f = frequency of the light = (5.49 × 10¹⁸) Hz

λ = wavelength of the light = ?

λ = (v/f) = (3.0 × 10⁸) ÷ (5.49 × 10¹⁸)

= (5.46 × 10⁻¹¹) m = 0.0546 nm

b) To find the wavelength of the light in diamond, we need the refractive index of diamond. This is because light, just like all other waves, change their velocities and subsequently their wavelengths in different materials according to the refractive index of the materials.

Refractive index of diamond = 2.42 (from literature)

2.42 = (wavelength of light in vacuum) ÷ (wavelength of light in diamond)

2.42 = 0.0546 ÷ λ

λ = 0.0546 ÷ 2.42 = 0.0226 nm

c) Energy of a photon in vacuum is given as

E = hf

where E = energy in Joules = ?

h = Planck's constant = (6.626 × 10⁻³⁴) J.s

f = frequency of the light in vacuum = (5.49 × 10¹⁸) Hz

E = (6.626 × 10⁻³⁴) × (5.49 × 10¹⁸) = (3.638 × 10⁻¹⁵) J

1 eV = (1.602 × 10⁻¹⁹) J

The amount of the calculated energy in eV

= (3.638 × 10⁻¹⁵) ÷ (1.602 × 10⁻¹⁹) = (2.271 × 10⁴) eV

d) As light travels from material to material, it's velocity and wavelength changes from material to material, but the frequency of the light waves stay the same. Since the energy of the photon depends solely on this frequency, it shows that the energy of the photon stays consistent in whichever material.

Hope this Helps!!!

3 0

3 years ago

In a reaction between vinegar and antacid tablets, the antacid is the limiting reagent. At constant pressure and temperature, th

lyudmila [28]

1200cm³ of gas

Explanation:

From the analogy provided in this problem,

we know that;

three tablets will produce 600cm³ of gas

This implies that;

1 tablet of the antacid will produce $\frac{600}{3}$ = 200cm³