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garik1379 [7]
3 years ago
13

a person touch a large chunk of ice with their hands and remarks. this is making me cold explain wat this person felling. is the

ice transferringcold to the person is there a heat transfer occuring? explain
Chemistry
1 answer:
k0ka [10]3 years ago
5 0
There is both. the persons body heat transfers to the ice while the cold transfers off the ice to the persons hand. thats why when you hold and ice cube for a long enough time it melts because your body heat melts it, while at the same time your hand starts to get colder.

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Indicate whether each statement is true or false: a. Substitutional alloys tend to be more ductile than interstitial alloys. b.
Masteriza [31]

Answer:

Substitutional alloys tend to be more ductile than interstitial alloys. true

Interstitial alloys tend to form between elements with similar ionic radii.false

Nonmetallic elements are never found in alloys. false

Explanation:

Substitutional alloys consists components having similar atomic(ionic) radii as well as common bonding characteristics. In interstitial alloys, atoms in interstitial positions must have a much smaller covalent radius than the solvent atoms. Interstitial atoms are generally less ductile than substitutional alloys.

Nonmetals are found in alloys. For instance, carbon is a component of the common alloy called steel.

3 0
3 years ago
Name two elements that you would expect to have properties very much like those of calcium
neonofarm [45]
Atoms in the same group (column) of the periodic table have similar properties. This is because all elements in the same group have the same amount of valence (outer) electrons.

So, any element directly above or below Calcium on the periodic table would have similar properties.

These would be Magnesium, Barium, Strontium, Radium, and Beryllium.
3 0
3 years ago
Does a light with low frequency and long wavelength have a lot or little energy?
Rudik [331]
The lower the frequncy the longer the wavelength the longer the wavelength whoch would probably give you more energy.

if im incorrect im truly sorry
7 0
3 years ago
For the following problem convert both the reactants to moles and balance chemical equationsThe reaction of 167 g Fe2O3 with 85.
saul85 [17]

Let's start by balancing the reaction:

Fe_2O_3+CO\longrightarrow Fe+CO_2

As we can see, C appears only on two comopunds, CO and CO₂, and since both have 1 C each, their coefficients have to be the same for C to be balanced. However, CO has 1 O and CO₂ has 2, so there is a difference of 1 O betwee them.

The other source of O is Fe₂O₃, that has 3 O. So, we must choose a coefficient for CO and CO₂ such that the difference between the numbers of O is a multiple of 3, that way we can fix this difference with the O from Fe₂O₃. So, we can put coefficients of 3 on both of them:

Fe_2O_3+3CO\longrightarrow Fe+3CO_2

That way, we maintained C balanced (3 on each side) and now we have 3 + 3 O on the left side and 6 O on the right side, so the same amount.

Now, we just have to calance Fe, but it is easy since we have it alone in Fe. Since we have 2 on the left side, it is enough to put a coefficient of 2 on Fe to get the balanced reaction:

Fe_2O_3+3CO\longrightarrow2Fe+3CO_2

Now, to convert from mass to number of moles, we need the molar masses of the reactants, which we can calculate from the atomic weights of the elemnts in each of them:

M_{Fe_2O_3}=2\cdot M_{Fe}+3\cdot M_O=(2\cdot55.845+3\cdot15.9994)g/mol=159.6882g/molM_{CO}=1\cdot M_C+1\cdot M_O=(1\cdot12.0107+1\cdot15.9994)g/mol=28.0101g/mol

Now, we can convert their masses to number of moles:

\begin{gathered} M_{Fe_{2}O_{3}}=\frac{m_{Fe_2O_3}}{n_{Fe_{2}O_{3}}} \\ n_{Fe_2O_3}=\frac{m_{Fe_2O_3}}{M_{Fe_{2}O_{3}}}=\frac{167g}{159.6882g/mol}=1.045787\ldots mol \end{gathered}\begin{gathered} M_{CO}=\frac{m_{CO}}{n_{CO}} \\ n_{CO}=\frac{m_{CO}}{M_{CO}}=\frac{85.8g}{28.0101g/mol}=3.063180\ldots mol \end{gathered}

Now, to determine the limiting reactant, we need to divide both the number of mole by their coefficients on the balanced reaction, so we can see how many we need per reaction of each:

\begin{gathered} Fe_2O_3\colon\frac{n_{Fe_2O_3}}{1}=\frac{1.045787\ldots mol}{1}=1.045787\ldots mol \\ CO\colon\frac{n_{CO}}{3}=\frac{3.063180\ldots mol}{3}=1.021060\ldots mol \end{gathered}

Now, the limiting reactant is the one we have less number of moles per reaction. We can see that we have less CO than Fe₂O₃, so the limiting reactant is CO.

4 0
1 year ago
Research the compositions of Pennies. What was the composition of each of your Pennies prior to treatment
LenKa [72]

Answer:

History of composition

Years Material Weight (grains)

1944–1946 gilding metal (95% copper, 5% zinc) 48 grains

1947–1962 bronze (95% copper, 5% tin and zinc) 48 grains

1962 – September 1982 gilding metal (95% copper, 5% zinc) 48 grains

October 1982 – present copper-plated zinc (97.5% zinc, 2.5% copper) 38.6 grains

7 0
2 years ago
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