Answer:
8 9.8 - 6.4n
9 15 - j/2
Step-by-step explanation:
8
2.8 - 4.4n - 2n +7
= 2.8+7 -4.4n -2n
= 9.8 - 6.4n
9
11 + (-3) - 1/8 j - 3/8 j +7
= 11 - 3 - 1/8 j - 3/8 j + 7
= 11 - 3 + 7 - 1/8 j - 3/8 j
= 15 - 4/8 j
= 15 - j/2
Correct question is;
Rosters Chicken advertises "lite" chicken with 30% fewer calories than standard chicken. When the process for "lite" chicken breast production is in control, the average chicken breast contains 450 calories, and the standard deviation in caloric content of the chicken breast population is 20 calories. Rosters wants to design an X-chart to monitor the caloric content of chicken breasts, where 25 chicken breasts would be chosen at random to form each sample. a) What are the lower and upper control limits for this chart if these limits are chosen to be four standard deviations from the target? b) What are the limits with three standard deviations from the target? Upper Control Limit (UCL)calories (enter your response as an integer).
Answer:
A)UCL = 466
LCL = 434
B)UCL = 462
LCL = 438
Step-by-step explanation:
We are given;
Mean;μ = 450
Standard deviation; σ = 20
Sample size; n = 25
A) We are told that these limits are chosen to be four standard deviations from the target.. This means that z-value = 4.
Thus, upper control limit will be the formula;
UCL = μ + 4σ/√n
UCL = 450 + 4(20)/√25
UCL = 450 + 16
UCL = 466
Lower control limit will be;
LCL = μ - 4σ/√n
LCL = 450 - 4(20)/√25
LCL = 450 - 16
LCL = 434
B) We are now told that these limits are chosen to be three standard deviations from the target.
Thus, z = 3
So;
UCL = μ + 3σ/√n
UCL = 450 + 3(20)/√25
UCL = 450 + 12
UCL = 462
Lower control limit will be;
LCL = μ - 3σ/√n
LCL = 450 - 3(20)/√25
LCL = 450 - 12
LCL = 438
Answer:
216 animals
Step-by-step explanation:
Let n represent the number of each type of animal.
Since there are two horses for every horse trough, then n must be divisible by 2. Since there are three cows for every cow trough, then n must be divisible by 3. Since there are eight pigs for every pig trough, then n must be divisible by 8. Therefore, n must be divisible by 2, 3 and 8. The smallest number divisible by 2, 3, and 8 is 24. (This number is called the lowest common multiple or LCM, for short.)
If there are 24 of each kind of animal, there would be 24 ÷ 2 = 12 troughs for horses, 24 ÷ 3 = 8 troughs for cows and 24 ÷ 8 = 3 troughs for pigs. This would require a total of 12 + 8 + 3 = 23 troughs. Since there are 69 troughs and
69 ÷ 23 = 3, we require 3 times more of each type of animal. That is, there would be 24 × 3 = 72 of each type of animal. The total number of animals is 72+72+72 or 216.
Therefore, McDonald has 216 animals.
Hope this helps :)
Not sure what the question is here is it an a/b question or do we have to do an answer for both a and b?
