The side lengths of quadrilateral are 21 inches; 11 inches; 11 inches; 7 inches.
<u>SOLUTION:</u>
Given, the perimeter of a quadrilateral (four-side polygon) is 50 inches.
Let the length of shortest side be n inches. The longest side is three times as long as the shortest side.
That is, length of largest side = 3n inches
The other two sides are equally long and are 4 inches longer than the shortest side.
Then, length of remaining two sides = 4 + n inches
We have to find the length of all four sides.
Now, we know that, perimeter = 50 inches

So, length of sides will be,

The answer would be linear..
Answer:
Solution given:
-2x²+7x-6=0
2x²-7x+6=0
Comparing above equation with ax²+bx+c
we get
a=2
b=-7
c=6
By using Vieta's theorem
X1+X2=
=
again
X1X2=
=
=3
Answer:
= 1/2
=
* 
Step-by-step explanation:
plug 1 into
=1/2(4/3)^n−1 to find 
=1/2(4/3)^1−1
= 1/2 (4/3)^0
= 1/2 * 1
= 1/2
=
* r where r is the ratio
since (4/3) is being taken to an exponent, (4/3) is r
=
* 
The answer is B.
ln both sides to clear the 'e' and bring 'a' out of the power.