Answer:
-2
step by step
(-3)^3-5(-3)+7-((2(-3)-3))
-27+15+7-(-6-3)
-27+15+7-(-3)
-27+15+7+3
-27+25
=-2
Answer:
y = 11
Step-by-step explanation:
Since our plane is parallel to the xz plane, the x and z are independent of each other, i.e. they could be anything. So xz plane has an equation of y = 0. So if this plane is located 11 units to the right of the xz plane then its equation must be y = 11.
Step-by-step explanation:
AD ≅ BC, Given
∠BCD ≅ ∠ADC, Given
CD ≅ CD, Reflexive property
ΔBCD ≅ ΔADC, SAS congruence
∠BDC ≅ ∠ACD, CPCTC
ΔECD is an isosceles triangle, definition of isosceles
DE ≅ CE, properties of isosceles triangles
Answer:
y = 3x + 2
Step-by-step explanation:
The equation for two points on a line is generated from the straight line equation y = mx + b ---------------- eqn (i)
where m, the slope = (y2 - y1) / (x2 - x1)
therefore for (0,2) and (1,5) m = (5 - 2)/(1 - 0) = 3
This implies that eqn (i) can be rewritten as:
y = 3x + b ------------------- eqn (ii)
pickintg the point (0,2) and substituting into eqn (ii)
2 = 3(0) + b
this implies that b = 2
for confirmation with (1,5)
5 = 3(1) + b
b = 5 - 3 = 2
hence m = 3, b = 2
the equation is y = 3x + 2
Answer:
$0.84
Step-by-step explanation:
120.96/144= 0.84
