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Nookie1986 [14]
3 years ago
7

Circle A: center (-4, 0) and radius 6

Mathematics
1 answer:
poizon [28]3 years ago
3 0

Answer:

Circle a must be translated (x+15, y+0) and then dilated by 4/6 in order to get circle b.

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What is the solution when <br> 9x+6y=-3<br><br> x+8y=29
Leya [2.2K]
We have
9x + 6y =  - 3 -  -  - (1)
and

x + 8y = 29
\rightarrow \: x = 29 - 8y -  -  - (2)


Using elimination will be faster, so plug in equation (2) in equation (1)

9(29 - 8y)  + 6y =  - 3

Expand brackets, we obtain,

261-72y+6y=-3
Simplifying gives,

-66y=-264

y =  \frac{ - 264}{ - 66}  = 4
x = 29 - 8(4) =  - 3

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4 years ago
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Nana76 [90]
1) 22.5

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The starting salary for a computer programmer major has a mean of $39,269 and a standard deviation of $2550. The probability tha
Nimfa-mama [501]

Answer:

The probability that a randomly selected programmer major received a salary less than 38000 is 0,3085

Step-by-step explanation:

We will assume that the salaries are Normally distributed. Lets call X the salary of a random major programmer in dollars. We want the pprobability of X being less than 38000. For it, we will standarize X. Lets call W the standarization, given by the formula

W = \frac{X-\mu}{\sigma}=\frac{X-39269}{2550}

Lets denote \phi the cumulative distribution function of the standard normal variable W. The values of \phi are well known and they can be found in the attached file. Now, lets calcualte the probability of X being less than 38000 using \phi

P(X

Since the density function of a standard normal random variable is symmetric, then \phi(-0.50) = 1-\phi(0.50) = 1-0.6915 = 0.3085

The probability that a randomly selected programmer major received a salary less than 38000 is 0,3085.

Download pdf
7 0
3 years ago
Read 2 more answers
How to solve linear and nonlinear equations graphically?
Ede4ka [16]
Plot the equation. If you wish to solve a polynomial, let y= polynomial and plot the graph. Best set up a table of values first.
Where the graph crosses the x axis there is a solution for x. There are also solutions for other horizontal lines (y values) by looking at intersections of the graph with these lines. This technique works for linear and non linear equations. You can also use graphs to solve 2-variable systems of equations by examining where the graphs intersect one another. The disadvantage is that you may not be able to have sufficient detail for high degrees of accuracy because of the scale of the graph and drawing inaccuracies.
8 0
3 years ago
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