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gulaghasi [49]
3 years ago
5

Ally and Christian bought 4 pounds of mulch and 2 pounds of seed for the garden how many ounces of these products did they purch

ase
Mathematics
2 answers:
irina [24]3 years ago
5 0
96 ounces of material.
Vlad [161]3 years ago
3 0
96 ounces of material
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Solve the following equation. 2/3x + 6 =1/2 x + 1/4x
MA_775_DIABLO [31]

Answer:

x = 72

Step-by-step explanation:

2/3x + 6 = 1/2x + 1/4x

2/3x + 6 = 3/4x

3/4 - 2/3 = 1/12

6 = 1/12x

Multiply 6 by 12 to get x

x = 72

8 0
3 years ago
Read 2 more answers
Approximate the area under the
taurus [48]

Split up the interval [0, 3] into 3 equally spaced subintervals of length \Delta x = \frac{3-0}3 = 1. So we have the partition

[0, 1] U [1, 2] U [2, 3]

The left endpoint of the i-th subinterval is

\ell_i = i - 1

where i\in\{1,2,3\}.

Then the area is given by the definite integral and approximated by the left-hand Riemann sum

\displaystyle \int_0^3 f(x) \, dx \approx \sum_{i=1}^3 f(\ell_i) \Delta x \\\\ ~~~~~~~~~~ = \sum_{i=1}^3 (i-1)^3 \\\\ ~~~~~~~~~~ = \sum_{i=0}^2 i^3 \\\\ ~~~~~~~~~~ = 0^3 + 1^3 + 2^3 = \boxed{9}

4 0
2 years ago
A sample of 200 observations from the first population indicated that x1 is 170. A sample of 150 observations from the second po
igor_vitrenko [27]

Answer:

a) For this case the value of the significanceis \alpha=0.05 and \alpha/2 =0.025, we need a value on the normal standard distribution thataccumulates 0.025 of the area on each tail and we got:

z_{\alpha/2} =1.96

If the calculated statistic |z_{calc}| >1.96 we can reject the null hypothesis at 5% of significance

b) Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{170+110}{200+150}=0.8  

c)z=\frac{0.85-0.733}{\sqrt{0.8(1-0.8)(\frac{1}{200}+\frac{1}{150})}}=2.708    

d) Since the calculated value satisfy this condition 2.708>1.96 we have enough evidence at 5% of significance that we have a significant difference between the two proportions analyzed.

Step-by-step explanation:

Data given and notation    

X_{1}=170 represent the number of people with the characteristic 1

X_{2}=110 represent the number of people with the characteristic 2  

n_{1}=200 sample 1 selected  

n_{2}=150 sample 2 selected  

p_{1}=\frac{170}{200}=0.85 represent the proportion estimated for the sample 1  

p_{2}=\frac{110}{150}=0.733 represent the proportion estimated for the sample 2  

\hat p represent the pooled estimate of p

z would represent the statistic (variable of interest)    

p_v represent the value for the test (variable of interest)  

\alpha=0.05 significance level given  

Concepts and formulas to use    

We need to conduct a hypothesis in order to check if is there is a difference between the two proportions, the system of hypothesis would be:    

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}    

We need to apply a z test to compare proportions, and the statistic is given by:    

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

a.State the decision rule.

For this case the value of the significanceis \alpha=0.05 and \alpha/2 =0.025, we need a value on the normal standard distribution thataccumulates 0.025 of the area on each tail and we got:

z_{\alpha/2} =1.96

If the calculated statistic |z_{calc}| >1.96 we can reject the null hypothesis at 5% of significance

b. Compute the pooled proportion.

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{170+110}{200+150}=0.8  

c. Compute the value of the test statistic.                                                                                              

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.    

Replacing in formula (1) the values obtained we got this:    

z=\frac{0.85-0.733}{\sqrt{0.8(1-0.8)(\frac{1}{200}+\frac{1}{150})}}=2.708    

d. What is your decision regarding the null hypothesis?

Since the calculated value satisfy this condition 2.708>1.96 we have enough evidence at 5% of significance that we have a significant difference between the two proportions analyzed.

5 0
3 years ago
Use the formula . Find t for r = 33.2 m/h and d = 375.16 m.
Butoxors [25]

\boxed{t=11.3h}

<h2>Explanation:</h2><h2></h2>

In this problem we have the following data:

r:speed \\ \\ d:distance \\ \\ t:time \\ \\ \\ r=33.2m/h \\ \\ d=375.16m \\ \\ \\ So \ our \ goal \ is \ to \ find \ t

Speed, time and distance are related with the following formula:

r=\frac{d}{t} \\ \\ \\ Solving \ for \ t: \\ \\ t=\frac{d}{r} \\ \\ t=\frac{375.16}{33.2} \\ \\ \boxed{t=11.3h}

<h2>Learn more:</h2>

Speed: brainly.com/question/14095729

#LearnWithBrainly

7 0
3 years ago
A small town had a population of 960 people last year. The population increased to 1200 people this year. By what percentage did
Licemer1 [7]

Answer:

25%

Step-by-step explanation:

25% of 960 is 240. to find that we need to do...

0.25 x 960 = 240

add the percent increace to the 960.....

960 + 240 = 1,200

Hope this helped! Please mark as brainliest! Thanks!!

8 0
3 years ago
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