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KATRIN_1 [288]
3 years ago
9

In △ABC, m∠A=50∘, m∠B=60∘, and m∠C=70∘.

Mathematics
1 answer:
kiruha [24]3 years ago
6 0

Given:

In \Delta ABC, m\angle A=50^\circ, m\angle B=60^\circ and m\angle C=70^\circ.

\Delta ABC is rotated 90^\circ counterclockwise to \Delta XYZ.

To find:

The measure of angle Z.

Solution:

We know that the rotation is a rigid transformation. It means the image and figure are congruent to each other.

\Delta ABC is rotated 90^\circ counterclockwise to \Delta XYZ. So, \Delta ABC\cong \Delta XYZ.

\angle C\cong \angle Z                      (CPCTC)

m\angle C=m\angle Z

70^\circ=m\angle Z

Therefore, the measure of angle Z is 70 degrees.

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Answer:

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hram777 [196]

Answer:

The number of students in the key club is 490

Step-by-step explanation:

The given parameters are;

The number of student in the school = 1000

The total number of student in the debate club = 310

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The total number of student who are in debate and student council = 170

The total number of student who are in both debate and the key club = 150

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The number of students who are in all three clubs = 50

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Let B represent the number of students in the student council

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n(A∪B∪C) = n(A) + n(B) + n(C) -  n(A∩B) - n(B∩C) - n(C∩A) + n(A∩B∩C)

Where;

n(A∪B∪C) = 1000

n(A) = 310

n(B) = 650

n(A∩B) = 170

n(B∩C) = 180

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n(A∩B∩C) = 50

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n(C) = n(A∪B∪C) - (n(A) + n(B) -  n(A∩B) - n(B∩C) - n(C∩A) + n(A∩B∩C))

Substituting the values gives;

n(C) = 1000 - (310 + 650 -  170 - 180 - 150 + 50) = 490

The number of students in the key club, n(C) = 490.

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