Question

Given the function h of x equals 8 times the cube root of x minus 6 end root plus 16, what is the x-intercept of the function?

Answer 1

The x-intercept of the function $h(x) = 8 * \sqrt[3]{x - 6} + 16$ is -2

How to determine the x-intercept?

The equation of the function is given as:

$h(x) = 8 * \sqrt[3]{x - 6} + 16$

The x intercept is the x value when h(x) = 0

So, we have:

$8 * \sqrt[3]{x - 6} + 16 = 0$

Subtract 16 from both sides

$8 * \sqrt[3]{x - 6} = -16$

Divide both sides by 8

$\sqrt[3]{x - 6} = -2$

Take the cube of both sides

x - 6 = -8

Add 6 to both sides

x = -2

Hence, the x-intercept of the function $h(x) = 8 * \sqrt[3]{x - 6} + 16$ is -2

Read more about x-intercept at:

brainly.com/question/3951754

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