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tiny-mole [99]
2 years ago
8

Given the function h of x equals 8 times the cube root of x minus 6 end root plus 16, what is the x-intercept of the function?

Mathematics
1 answer:
xz_007 [3.2K]2 years ago
3 0

The x-intercept of the function h(x) = 8 * \sqrt[3]{x - 6} + 16 is -2

<h3>How to determine the x-intercept?</h3>

The equation of the function is given as:

h(x) = 8 * \sqrt[3]{x - 6} + 16

The x intercept is the x value when h(x) = 0

So, we have:

8 * \sqrt[3]{x - 6} + 16 = 0

Subtract 16 from both sides

8 * \sqrt[3]{x - 6} = -16

Divide both sides by 8

\sqrt[3]{x - 6} = -2

Take the cube of both sides

x - 6 = -8

Add 6 to both sides

x = -2

Hence, the x-intercept of the function h(x) = 8 * \sqrt[3]{x - 6} + 16 is -2

Read more about x-intercept at:

brainly.com/question/3951754

#SPJ1

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