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3 years ago

What percent of students prefer burgers?

Mathematics

1 answer:

AleksandrR [38]3 years ago

4 0

Answer:

40 (without the percent sign because the question doesn’t want you to put it)

Step-by-step explanation:

This is a very reasonable diagram because the 216˚ plus the 144˚ equal 360˚, which is sensible because a circle is 360˚ (degrees). So, you can just do 144 divided by 360 to find the percent of the circle, which equals 0.4, and 0.4 as a percent is 40%. But the question doen’t want to you to put the percent sign. So the answer is just 40.

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Please help the picture is

asambeis [7]

The walls are vertical so the angle opposite X would be a right angle which is 90 degrees.

X would be 180 - 90 - 35 = 55 degrees

X and 2y - 5 are complementary angles which add together to equal 90:

2y - 5 + 55 = 90

Simplify:

2y +50 = 90

Subtract 50 from both sides:

2y = 40

Divide both sides by 2:

y = 20

7 0

3 years ago

Read 2 more answers

I need help with this question please help. Its gt geometry

Savatey [412]

Answer: First one is 140, second one is 70

Step-by-step explanation: They’re corresponding angles

7 0

3 years ago

An animal shelter has $2500 in its reserve fund. The shelter charges $40 per animal placement and would like to have at least $4

densk [106]

Answer:

Step 1

Write and solve the inequality:

2,500 + 40a ≥ 4,000, or 40a ≥ 1,500

a ≥ 37.5

Step 2

If the shelter places 30 cats and 10 dogs,

or 40 animals, that will be enough to meet

its goal, because a = 40 is a solution to the

inequality a ≥ 37.5.

5 0

3 years ago

Which of the following are the factors of q3 – q2 + 2q – 2?

alexdok [17]

$x {}^{3} - x {}^{2} + 2x - 2 \\ \\ x {}^{2} (x - 1) + 2(x - 1) \\ \\ (x - 1)(x {}^{2} + 2)$

5 0

3 years ago

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Jenny and Natalie are selling cheesecakes for a school fundraiser. Customers can buy chocolate cakes and vanilla cakes. Jenny so

IrinaVladis [17]

The cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

Solution:

Let "c" be the cost of 1 chocolate cake

Let "v" be the cost of 1 vanilla cake

Jenny sold 14 chocolate cakes and 5 vanilla cakes for 119 dollars

Therefore, we can frame a equation as:

14 x cost of 1 chocolate cake + 5 x cost of 1 vanilla cake = 119

$14 \times c + 5 \times v=119$

14c + 5v = 119 ------- eqn 1

Natalie sold 10 chocolate cakes and 10 vanilla cakes for 130 dollars

Therefore, we can frame a equation as:

10 x cost of 1 chocolate cake + 10 x cost of 1 vanilla cake = 130

$10 \times c + 10 \times v = 130$

10c + 10v = 130 -------- eqn 2

Let us solve eqn 1 and eqn 2

Multiply eqn 1 by 2

28c + 10v = 238 ------ eqn 3

Subtract eqn 2 from eqn 3

28c + 10v = 238

10c + 10v = 130

( - ) --------------------------

18c = 108

c = 6

Substitute c = 6 in eqn 1

14(6) + 5v = 119

84 + 5v = 119

5v = 119 - 84

5v = 35

v = 7

Thus cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

8 0

3 years ago