Answer:
23 boxes of toys are being stored.
Step-by-step explanation:
There is a fixed cost of $1200 a month for rent and a variable cost of $5 per box of toys that are stored
This means that for x boxes of toys stored, the total cost is of:
![C(x) = 1200 + 5x](https://tex.z-dn.net/?f=C%28x%29%20%3D%201200%20%2B%205x)
If the total cost for this month was $1315, how many boxes of toys are being stored?
This is
for which
. So
![C(x) = 1200 + 5x](https://tex.z-dn.net/?f=C%28x%29%20%3D%201200%20%2B%205x)
![1315 = 1200 + 5x](https://tex.z-dn.net/?f=1315%20%3D%201200%20%2B%205x)
![5x = 115](https://tex.z-dn.net/?f=5x%20%3D%20115)
![x = \frac{115}{5}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B115%7D%7B5%7D)
![x = 23](https://tex.z-dn.net/?f=x%20%3D%2023)
23 boxes of toys are being stored.
Answer:
2
Step-by-step explanation:
this might be the rong answer
Let amount invested at 8% per year = x
Let amount invested at 14% per year = y
Total investment is $94000 then we get equation:
x+y=94000
or
x=94000-y...(i)
Given that total return in 1 year is $8720 so we can write equation:
8% of x + 14% of y = 8720
or
0.08x+0.14y=8720...(ii)
plug (i) into (ii)
0.08(94000-y)+0.14y=8720
7520-0.08y+0.14y=8720
7520+0.06y=8720
0.06y=8720-7520
0.06y=1200
y=20000
plug value of y into (i)
x=94000-y=94000-20000=74000
Hence final answer is given by:
Amount invested at 8% per year = $74000
Amount invested at 14% per year = $20000
Answer:
C = 39
Step-by-step explanation:
From the question given above, the following data were obtained:
A = 2x + 108
B = x + 33
C =?
Next, we shall obtain an expression for C. This can be obtained as follow:
A + B + C = 180 (sum of angles in a triangle)
2x + 108 + x + 33 + C = 180
2x + x + 108 + 33 + C = 180
3x + 141 + C = 180
Make C the subject by rearranging
C = 180 – 141 – 3x
C = 39 – 3x
Next, we shall determine the value of x. This can be obtained as follow:
A = 2x + 108
B = x + 33
C = 39 – 3x
A + B + C = 180
2x + 108 + x + 33 + 39 – 3x = 180
2x + x – 3x + 108 + 33 + 39 = 180
3x – 3x + 180 = 180
3x – 3x = 180 – 180
3x – 3x = 0
x(3 – 3) = 0
x(0) = 0
x = 0
Finally, we shall determine C. This can be obtained as follow:
C = 39 – 3x
x = 0
C = 39 – 3(0)
C = 39 – 0
C = 39