Determine the Probability: P(B^c)
1 answer:
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The cost of children’s ticket is $ 5
<h3><u>Solution:</u></h3>Let "c" be the cost of one children ticket
Let "a" be the cost of one adult ticket
Given that adult ticket to a museum costs 3$ more than a children’s ticket
<em>Cost of one adult ticket = 3 + cost of one children ticket</em>
a = 3 + c ------ eqn 1
<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>
200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100
200a + 100c = 2100 ------ eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>
Substitute eqn 1 in eqn 2
200(3 + c) + 100c = 2100
600 + 200c + 100c = 2100
600 + 300c = 2100
300c = 1500
<h3>c = 5</h3>Thus the cost of children’s ticket is $ 5
Answer: 1. 3801
Step-by-step explanation:
Log 24 = Log(8x3)
From the laws of Logarithm
Log ( a xb) = Log a + Log b
so, Log (8x3) = Log8 + Log 3
Also Log 8 can be written as Log since
is still 8 , so the expression becomes
Log + Log 3
⇒ 3 Log 2 + Log 3
since the value of Log 2 and Log 3 has been given , substitute into the expression , we have
3 (0.3010) + 0.4771
= 0.903 + 0.4771
= 1.3801