Answer:
Step-by-step explanation:
Hope this helps!
For a number to be a multiple of 6, it must be divisible by 6
and a number divisble by 6 means that it is divisble by 2 and 3
since the ones digit is odd it is not divisble by 2 which means 61 is not a multiple of 6
Answer:
32.99
Step-by-step explanation:(you might have to round) if you have to round it or.. but this is it because
236.40 divided by 24 is 9.85 so
325 divided by 9.85 is 32.99 (you only need 2 decimal places for these kinds of questions because of repeating decimals).
Hope this helps :)
Answer: See below
Step-by-step explanation:
27. -(a-3)
28. (b-1)(b+3)
29. (c+4)(c+5)
30. d(d+5)
31. -(3/4)(2e-5)
Sorry - I don't have time to enter the details. Look for areas where the expressions can be factored in a manner that forms as many equivalent expressions in both the numerator and denominator.
For example: In problem 30:
(5d-20)/(d^2+d-20) * [??]/20d = 1/4
Factor:
<u>(5(d-4))</u> <u>d(d+5)</u> = 1/4
(d-4)(d+5<u>)</u> 20d
The (d-4), d+5, and d terms cancel, leaving
5/20 = 1/4
Answer:
11, 60.61
Step-by-step explanation:
this is the only set that fits a^2 +b^2=c^2
you square the first two numbers, add them together. Then you take the square root of that sum. This number must equal the third number for it to be a triple.
