Hi! I'm confused as to how to get the answer for this -> 3(y+7) = 2y

How can you use place value to describe how 0.05 and 0.005 compare

zvonat [6]

0.05 is 10 times greater than 0.005

6 0

3 years ago

Read 2 more answers

one third of the sum of two angles is 60 degree and one quarter of their difference is 28 degree. find the two angles

vlabodo [156]

1/3(a + b) = 60
a + b = 60 * 3 = 180

1/4(a - b) = 28
a - b = 28 * 4 = 112

a + b = 180
a - b = 112
---------------add
2a = 292
a = 292/2
a = 146

a + b = 180
146 + b = 180
b = 180 - 146
b = 34

so ur 2 angles are : 146 and 34

7 0

3 years ago

A sample of blood pressure measurements is taken for a group ofadults, and those values (mm Hg) are listed below. The values a

scoundrel [369]

Answer:

1. coefficient of variation(systolic) = 13.88%

2. coefficient of variation(diastolic) = 16.2%

3. The coefficients of variation for each data set are within 5 percentage points of each other Therefore the systolic measurements vary signifcantly less than the diastolic

Step-by-step explanation:

1. Mean of systolic = ( 117+126+158+96+157+122+116+134+127+122)÷10

= 127.5

Standard Deviation of systolic = (((117-127.5)^2 +(126-127.5)^2+(158-127.5)^2+ (96-127.5)^2 + (157-127.5)^2 + (122-127.5)^2 + (116-127.5)^2 +(134-127.5)^2 +(127-127.5)^2 +( 122-127.5)^2) ÷ 10)^(0.5)

SD = 17.7

coefficient of variation(systolic)

= Standard Deviation of systolic /mean of systolic

= $\frac{17.7}{127.5} * 100$

coefficient of variation(systolic) = 13.88%

2. Mean of diastolic = ( 80+77+76+51+90+89+60+64+72+83) ÷ 10

= 74.2

Standard Deviation of diastolic = (((80-74.2)^2 +(77-74.2)^2+(76-74.2)^2+ (51-74.2)^2 + (90-74.2)^2 + (89-74.2)^2 + (60-74.2)^2 +(64-74.2)^2 +(72-74.2)^2 +(83-74.2)^2) ÷ 10)^(0.5)

SD = 12

coefficient of variation(diastolic)

= Standard Deviation of diastolic /mean of diastolic

= $\frac{12}{74.2} *100$

coefficient of variation(diastolic) = 16.2%

3. The coefficients of variation for each data set are within 5 percentage points of each other Therefore the systolic measurements vary signifcantly less than the diastolic

8 0

2 years ago

Directions-Write an exponential function to model each situation. Then find the value of the function after the given amount of

nignag [31]

Answer:

We can now write this is a function of time in years leading to

f

(

x

)

=

200

(

.94

)

x

f

(

5

)

≈

147

Explanation:

Firs you should consider that if its exponential then it has some form similar to

3

x

. Where we have some known part (3) and the unknown part (

x

) that we are trying to find out. Mathematically we can say it has the form

a

x

. In this case we know what the

a

is and that is the entire population that was given to us. We know over time it will change but why are we even using the exponential model.

Well it turns out that if you multiply some value over and over again it has this form. Example we multiply

2

⋅

2

⋅

2

⋅

2

=

2

4

. So if something doubled over time then this is what would happen.

Now the problem is that it will continue to decrease at the same rate leading to

a

⋅

(

.94

)

because only

94

%

of the population remains each year. After two years

a

⋅

(

.94

)

⋅

(

.94

)

. We can now write this is a function of time in years leading to

f

(

x

)

=

200

⋅

(

.94

)

x

f

(

5

)

≈

147

Step-by-step explanation:

8 0

1 year ago

In Exercises 1–4, use these results from a USA Today survey in which 510 people chose to respond to this question that was poste

Alexus [3.1K]

Answer:

The proportion of the population believes that passwords should be replaced with biometric security is not more than 50%.

Step-by-step explanation:

In this case we need to test the claim that more than half of the population believes that passwords should be replaced with biometric security.

Assume that the significance level of the test is, α = 0.05.

The hypothesis can be defined as follows:

H₀: The proportion of the population believes that passwords should be replaced with biometric security is 50%, i.e. p = 0.50.

Hₐ: The proportion of the population believes that passwords should be replaced with biometric security is more than 50%, i.e. p > 0.50.

The information provided is:

$n = 510\\\hat p=0.53$

Compute the test statistic value as follows:

$z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}$

$=\frac{0.53-0.50}{\sqrt{\frac{0.50(1-0.50)}{510}}}\\\\=1.354991\\\\\approx 1.35$

The test statistic value is 1.35.

The decision rule is:

The null hypothesis will be rejected if the p-value of the test is less than the significance level.

Compute the p-value as follows:

$p-value=P(Z>1.35)$

$=1-P(Z$

p-value = 0.088 > α = 0.05.

The null hypothesis will not be rejected at 5% significance level.

Thus, there is not enough evidence to support the claim.

Conclusion:

The proportion of the population believes that passwords should be replaced with biometric security is not more than 50%.

7 0

2 years ago

Hi! I'm confused as to how to get the answer for this -> 3(y+7) = 2y - 5