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Fantom [35]
3 years ago
15

Given z1 =9+9/3i and z2 = 2+/3i, what is z2-z1?

Mathematics
1 answer:
diamong [38]3 years ago
6 0

Answer:

z2 - z1 = 7/3i

Step-by-step explanation:

Given the following complex number:

z1 = 9+i/3i

z2 =  2+i/3i,

Taking the difference

z2 - z1 = 9+i/3i - (2+i))/3i)

z2-z1 = (9+i-(2+i))/31

z2 - z1 = 9+i -2-i/3i

z2-z1 = 9-2/3i

z2 - z1 = 7/3i

<em>Note that the complex number given was not properly written and the ones used were assumed. Same procedure an be used for other complex numbers that might be given.</em>

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