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Harlamova29_29 [7]

3 years ago

5

A 40-foot tree casts a shadow 60 feet long. How long would the shadow of a 6-foot man be at that time?

2 answers:

Andre45 [30]3 years ago

4 0

Answer:

26 ft

Step-by-step explanation:

I'm guessing this is how it's done

60-40= 20

there for at this time any shadow would be 20x it's original height/length

so 6+20=26 ft

lmk if I'm correct

anzhelika [568]3 years ago

3 0

Taking ratios

Let the shadow length=x ft

$\\ \sf\longmapsto 40:60=6:x$

$\\ \sf\longmapsto \dfrac{40}{60}=\dfrac{6}{x}$

$\\ \sf\longmapsto \dfrac{4}{6}=\dfrac{6}{x}$

$\\ \sf\longmapsto 4x=6(6)$

$\\ \sf\longmapsto 4x=36$

$\\ \sf\longmapsto x=\dfrac{36}{4}$

$\\ \sf\longmapsto x=9$

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Amanda is practicing her dives off the diving board. When she dives into the water, the path her body makes and where she resurf

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Answer:

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Step-by-step explanation:

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6 0

3 years ago

Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

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For a vector

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Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

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<em></em> $\theta = 108.29$ <em> (approximated)</em>

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