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Verizon [17]
3 years ago
12

Evaluate-2x3 - 2x2 - 4x-2 for x=-2. A.-18 B. 16 C. -2 D. 14

Mathematics
1 answer:
dmitriy555 [2]3 years ago
4 0

Answer:

14

Step-by-step explanation:

-2x^3 - 2x^2 - 4x-2

Let x = -2

-2 (-2)^3 - 2 (-2)^2 -4(-2) -2

Exponents first

-2 (-8) -2 (4) -4(-2) -2

Then multiply

16 -8 +8 -2

Then add and subtract

14

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the answer is 10.6

Step-by-step explanation:


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Danielle is x years old. Her sister is 5 years older and her brother is half Danielle's age. Write an expression in simplest for
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Step-by-step explanation:

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How do I solve this algebra two btw
pychu [463]

\bf \begin{cases} x^2+y^2=400\\ \boxed{y}=x-28 \end{cases}\qquad \stackrel{\textit{substituting on the 1st equation}}{x^2+\left( \boxed{x-28} \right)^2=400} \\\\\\ x^2+(x^2-56x+28^2)=400\implies x^2+x^2-56x+28^2=400 \\\\\\ 2x^2-56x+784=400\implies 2x^2-56x+384=0 \\\\\\ 2(x^2-28x+192)=0\implies x^2-28x+192=0 \\\\\\ (x-16)(x-12)=0\implies x = \begin{cases} 16\\ 12 \end{cases}

now that we know what are the x-values, what are the y-values? well, we can just use the 2nd equation, since we know that y = x - 28, then

\bf y = x - 28\implies \stackrel{\textit{when x = 16}}{y = 16 - 28}\implies y = -12 \\\\\\ y = x - 28\implies \stackrel{\textit{when x = 12}}{y = 12 - 28}\implies y = -16 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (\stackrel{x}{16}~~,~~\stackrel{y}{-12})\qquad,\qquad (\stackrel{x}{12}~~,~~\stackrel{y}{-16})~\hfill

7 0
3 years ago
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