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creativ13 [48]
3 years ago
7

3 12 27 48. what is the rule?​

Mathematics
2 answers:
Shkiper50 [21]3 years ago
8 0

Answer:

Step-by-step explanation:

3(1)^2=3, 3(2)^2=12, 3(3)^2=27, 3(4)^2=48

f(n)=3n^2, n≥1

pshichka [43]3 years ago
3 0

Answer:

this rule follow the airthmatics progression.

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1 < third side < 7




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A mixture of compounds X and Y in a 0.100-cm cell had an absorbance of 0.215 at 272 nm and 0.191 at 327 nm. Find [X] and [Y] in
Oksi-84 [34.3K]

Answer: The concentration of X is 7.13582\times 10^{-6} and the concentration of Y is 2.53159\times 10^{-5}.

Step-by-step explanation:

Since we have given that

At 272 nm, absorbance = 0.215

At 327 nm, absorbance = 0.191

As we have given that

                               Compound X             Compound Y

272                               16400                            3870

327                                3990                             6420

So, our equations becomes

16400C_1+3870c_2=0.215\\\\3990C_1+6420C_2=0.191

By solving these two equations, we get that

C_1=7.13582\times 10^{-6}\\\\C_2=2.53159\times 10^{-5}

Hence, the concentration of X is 7.13582\times 10^{-6} and the concentration of Y is 2.53159\times 10^{-5}.

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3 years ago
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