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Dovator [93]
3 years ago
11

029494737+8489949494

Mathematics
2 answers:
Pani-rosa [81]3 years ago
5 0

Answer:

8519444231

Step-by-step explanation:

my brainlest plz

skelet666 [1.2K]3 years ago
4 0

Answer:

8519444231

I hope this helps!

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On any given day, the number of users, u, that access a certain website can be represented by the inequality 125-4530
Masteriza [31]

Answer:

Step-by-step explanation:

Our inequality is |125-u| ≤ 30. Let's separate this into two. Assuming that (125-u) is positive, we have 125-u ≤ 30, and if we assume that it's negative, we'd have -(125-u)≤30, or u-125≤30.

Therefore, we now have two inequalities to solve for:

125-u ≤ 30

u-125≤30

For the first one, we can subtract 125 and add u to both sides, resulting in

0 ≤ u-95, or 95≤u. Therefore, that is our first inequality.

The second one can be figured out by adding 125 to both sides, so u ≤ 155.

Remember that we took these two inequalities from an absolute value -- as a result, they BOTH must be true in order for the original inequality to be true. Therefore,

u ≥ 95

and

u ≤ 155

combine to be

95 ≤ u ≤ 155, or the 4th option

4 0
3 years ago
What decimal can be added to 0.0(54) to get 0.1(54)? (the parenthesis mean repeating)
son4ous [18]
Add 0.1 to 0.0(54) to get 0.1(54).
5 0
3 years ago
Read 2 more answers
A circular pond 20m in diameter is surrounded by a gravel path 5m wide. The path is to be replaced by a brick walk costing $30 p
Bezzdna [24]
Here, check this out.

8 0
3 years ago
Read 2 more answers
Given that a=4 and b=5. evaluate : a²+3b​
andreev551 [17]

Answer:

31

Step-by-step explanation:

4 squared is 16, and 5 times 3 is fifteen if you add them you get 31

3 0
3 years ago
Read 2 more answers
PLEASE HELP I WILL MARK BRAINLIEST!<br> Question is in the image.
deff fn [24]

Answer:

8

Step-by-step explanation:

The interquartile range of a data set is the difference between the upper and lower quartiles.

First, put the values in order from least to greatest:

8, 9, 9, 9, 10, 11, 13, 15, 17, 18, 22

To find the upper quartile, we need to first find the median.

The median of this data set is 11, because it is in the middle of the values.

The upper quartile is the median of all the numbers to the left of 11.

The median of 8, 9, 9, 9, and 10 is 9, because it's in the middle.

So the upper quartile is 9.

The lower quartile is the same, but to the right of 11. The median of 13, 15, 17, 18, and 22 is 17 because it's in the middle.

Now, to find the interquartile range, find the difference between 18 and 9.

17 - 9 = 8

5 0
3 years ago
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