All categories

3 years ago

Alicia is a nurse.

Mathematics

1 answer:

amm18123 years ago

4 0

AnswerAverage pay per hour 19.15

Step-by-step explanation:

1750 + 2% = 1785 pay increase

1785 x 12 months = 21420 a year

21420 divided by 52 weeks in a year averages to 411.92 weekly

Divide 411.92 by the 45 hours of work is 19.15 per hour

Brainliest please, if correct.

You might be interested in

Tomio, age 28, takes out $50,000 of straight-life insurance. His annual premium is $418.20. Using the tables found in the textbo

olya-2409 [2.1K]

Tomio, age 28, takes out $50,000 of straight-life insurance. His annual premium is $418.20. Using the tables found in the textbook, determine the cash value of his policy at the end of 20 years.

A. $26,500
B. $30,000
C. $13,250
D. $26,000

50,000/1,000 = 50
265*50 = $13,250

So the cash value of this policy is $13,250

The correct answer is:
C. $13,250

6 0

4 years ago

Read 2 more answers

What is not equivalent to 2 and 1/10

ivann1987 [24]

Not equal to 2 and 1/10

3 and 1/2

Answer: 3 and 1/2

7 0

4 years ago

What fraction is greater than C on the given number line above?

Ghella [55]

Answer:

2/5

Step-by-step explanation:

C is at the second tick of 6 segements, so C = 2/6 = 1/3.

If we convert all fractions to /60, you can easily see the answer:

1/3 = 20/60

2/5 = 24/60

1/4 = 15/60

1/5 = 12/60

So we're looking for an answer larger than 20/60, which is only 24/60, a.k.a. 2/5.

4 0

3 years ago

Read 2 more answers

Let M be the closed surface that consists of the hemisphere

ycow [4]

Since $M$ is closed, you can use the divergence theorem: The flux of $\vec E(x,y,z)$ across $M$ is

$\displaystyle\iint_{\partial M}\vec E\cdot\mathrm d\vec S=\iiint_M(\nabla\cdot\vec E)\,\mathrm dV=54\iiint_M\mathrm dV$

which is 54 times the volume of the hemisphere centered at (0, 0, 0) with radius 1, $\boxed{36\pi}$ .

Judging by the question content, you're supposed to find this value by computing the the integral of $\vec E$ across $M_1$ and $M_2$ .

Across $M_1$ :

Parameterize the hemisphere by

$\vec r(u,v)=(\cos u\sin v,\sin u\sin v,\cos v)$

with $0\le u\le2\pi$ and $0\le v\le\frac\pi2$ . Take the normal vector to $M_1$ to be

$\dfrac{\partial\vec r}{\partial v}\times\dfrac{\partial\vec r}{\partial u}=(\cos u\sin^2v,\sin u\sin^2v,\sin v\cos v)$

The flux of $\vec E$ across $M_1$ is

$\displaystyle\iint_{M_1}\vec E\cdot\mathrm d\vec S=18\int_0^{\pi/2}\int_0^{2\pi}(\cos u\sin v,\sin u\sin v,\cos v)\cdot\left(\dfrac{\partial\vec r}{\partial v}\times\dfrac{\partial\vec r}{\partial u}\right)\,\mathrm du\,\mathrm dv$

$=\displaystyle18\int_0^{\pi/2}\int_0^{2\pi}\sin v\,\mathrm du\,\mathrm dv=36\pi$

Across $M_2$ :

Parameterize the disk by

$\vec s(u,v)=(u\cos v,u\sin v,0)$

with $0\le u\le1$ and $0\le v\le2\pi$ . Take the normal to $M_2$ to be

$\dfrac{\partial\vec s}{\partial v}\times\dfrac{\partial\vec u}{\partial v}=(0,0,-u)$

Then the flux across $M_2$ is

$\displaystyle\iint_{M_2}\vec E\cdot\mathrm d\vec S=18\int_0^{2\pi}\int_0^1(u\cos v,u\sin v,0)\cdot\left(\frac{\partial\vec s}{\partial v}\times\frac{\partial\vec s}{\partial u}\right)\,\mathrm du\,\mathrm dv=0$

Then the total flux across $M$ is $36\pi$ , as expected.

4 0

3 years ago

In Exercises 15 and 16, tell whether the triangle with the given side

Nata [24]

15. 10 cm, 10 cm, V200 cm : Right Angled Triangle

16. 9 in., 16 in., 25 in. : Not a right angled triangle

Step-by-step explanation:

In order to check whether the given sides form a right angled triangle, we check if the sum of squares of two shorter sides is equal to the square of third longest side.

15. 10 cm, 10 cm, V200 cm

$The\ shorter\ sides\ are\ 10cm\ and\ 10cm\\Let \\a=10\\b=10\\c=\sqrt{200}So,\\c^2=a^2+b^2\\(\sqrt{200})^2=(10)^2+(10)^2\\200 = 100+100\\200 = 200$

The triangle is a right angled triangle.

16. 9 in., 16 in., 25 in.

Here

a = 9 in

b=16 in

c=25 in

So,

$c^2=a^2+b^2\\(25)^2=(9)^2+(16)^2\\625=81+256\\625=337$

The given triangle is not a right angled triangle.

Keywords: Triangle, Right angled Triangle

Learn more about triangle at:

#LearnwithBrainly

3 0

4 years ago