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3 years ago

Can you write a binomial in standard form with a degree of 0?

1 answer:

8 0

Any non-zero expression raised to the power of 0 will become 1, which is a single term and can be considered a monomial. So the answer is no.

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Please hurry attachment below will Brainly if answer correctly 30 POINTS

Rzqust [24]

Put everything into a calculator to change to decimal form to make things easier:
27/5=5.4
5.36=5.36
5 3/5=5.6
33/6=5.5
So now in order to least to greatest it would be:
5.36, 27/5, 33/6, 5 3/5

6 0

3 years ago

What is the slope of the line?

boyakko [2]

Answer:

the slope is 4

Step-by-step explanation:

look at the dotted lines. to determine the slope with a graph you must use rise over run. this is the fastest way to determine the slope using a graph.

6 0

4 years ago

Read 2 more answers

Find the average value of the function on the given interval.<br> f(x)=(2x-1)1/2; [1,13]

Leni [432]

Answer:

The average value of the function on the given interval 6.5.

Step-by-step explanation:

Consider the given function is

$f(x)=\dfrac{2x-1}{2}$

We need to find the average value of the function on the given interval [1,13].

$f(x)=\dfrac{2x}{2}-\dfrac{1}{2}$

$f(x)=x-0.5$

The average value of the function f(x) on [a,b] is

$Average=\dfrac{1}{b-a}\int\limits^b_a {f(x)} \, dx$

Average value of the function on the given interval [1,13] is

$Average=\dfrac{1}{13-1}\int\limits^{13}_{1} {x-0.5} \, dx$

$Average=\dfrac{1}{12}[\dfrac{x^2}{2}-0.5x]^{13}_{1}$

$Average=\dfrac{1}{12}[\dfrac{(13)^2}{2}-0.5(13)-(\dfrac{(1)^2}{2}-0.5(1))]$

$Average=\dfrac{1}{12}[78-0]$

$Average=6.5$

Therefore, the average value of the function on the given interval 6.5.

6 0

3 years ago

Can someone help me pls

kozerog [31]

Answer:

im not sure about this one but I think its 45°

6 0

3 years ago

Read 2 more answers

Last year, Theodora estimated that she would sell 96 bracelets. But at the end of the year, she had 16 bracelets left over. Whic

Likurg_2 [28]

%error=100(estimated-actual)/actual

%error=100(96-(96-16))/(96-16)

%error=100(16/80)

%error=1600/80

%error=20%

She overestimated how many bracelets she would sell by 20%

8 0

4 years ago

Read 2 more answers