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3 years ago

Need answer please ASAP

Mathematics

1 answer:

rusak2 [61]3 years ago

8 0

Answer:

Step-by-step explanation:

First you need to do your equation to..... =0 first

So you just minus 13 from 22 and get 9

Then you just do your completing the square

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Convert improper fraction to a mixed number<br> 9/2

harkovskaia [24]

2 goes into 9 4 times. So 4 is your large number and you have 1 remaining, put that over the denominator and your answer is 4 1/2

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3 years ago

Given below is the odd-number function. Which of the following are equal to O(8)?

dezoksy [38]

The answer would be B.
For these, you plug in 8 where there ia a variable. 2(8)-1=15

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4 years ago

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Can some one help on 30? thx

MariettaO [177]

The lowest common multiple of 2 and 7 is 14, so 14 days will pass before he does both chores again.

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3 years ago

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1. Evaluate the function f(x)=3x-1 using the domain of -2, 0, 3, and 5. Results are to be shown in a table.

IceJOKER [234]

Answer:

See explanation

Step-by-step explanation:

You are given the function $f(x)=3x-1$

The domain of the function are all possible values of variable x, so you can find f(x) for x=-2, 0, 3, 5:

$f(-2)=3\cdot (-2)-1=-6-1=-7\\ \\f(0)=3\cdot 0-1=0-1=-1\\ \\f(3)=3\cdot 3-1=9-1=8\\ \\f(5)=3\cdot 5-1=15-1=14$

The table is

$\begin{array}{cc}x&f(x)\\-2&-7\\0&-1\\3&8\\5&14\end{array}$

The inverse function $f^{-1}(x)$ has the domain which is the range of the function f(x) (all possible values of f(x)), so the domain of inverse function is {-7,-1,8,14}

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3 years ago

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Simplify the expression state any excluded values<br> 2a^2-4a+2<br> ---------------<br> 3a^2-3

chubhunter [2.5K]

Answer:

The simplified form is $\dfrac{2(x-1)}{3(x+1)}$ .

$x =1$ is the excluded value for the given expression.

Step-by-step explanation:

Given:

The expression given is:

$\dfrac{2a^2-4a+2}{3a^2-3}$

Let us simplify the numerator and denominator separately.

The numerator is given as $2a^2-4a+2$

2 is a common factor in all the three terms. So, we factor it out. This gives,

$=2(a^2-2a+1)$

Now, $a^2-2a+1=(a-1)(a-1)$

Therefore, the numerator becomes $2(a-1)(a-1)$

The denominator is given as: $3a^2-3$

Factoring out 3, we get

$3(a^2-1)$

Now, $a^2-1$ is of the form $a^2-b^2=(a-b)(a+b)$

So, $a^2-1=(a-1)(a+1)$

Therefore, the denominator becomes $3(a-1)(a+1)$

Now, the given expression is simplified to:

$\frac{2a^2-4a+2}{3a^2-3}=\frac{2(x-1)(x-1)}{3(x-1)(x+1)}$

There is $(x-1)$ in the numerator and denominator. We can cancel them only if $x\ne1$ as for $x=1$ , the given expression is undefined.

Now, cancelling the like terms considering $x\ne1$ , we get:

$\dfrac{2a^2-4a+2}{3a^2-3}=\dfrac{2(x-1)}{3(x+1)}$

Therefore, the simplified form is $\dfrac{2(x-1)}{3(x+1)}$

The simplification is true only if $x\ne1$ . So, $x =1$ is the excluded value for the given expression.

8 0

4 years ago