Answer:
The solution is the point (1,-4)
Step-by-step explanation:
we have
----> equation A
----> equation B
we know that
The solution of the system of equations by graphing is the intersection point both graphs
using a graphing tool
The intersection point is (1,-4)
see the attached figure
therefore
The solution is the point (1,-4)
Okay well here's what I got.
Hoped It Helped
:)
Answer:
None of the above
Explanation:
To find the type of lines they create, first find the slope of the equations.(Change form to y intercept)
4x-2y=-5
-2y=-4x-5
y=2x+(5/2)
Slope=2
-2x+3y=-3
3y=2x-3
y=(2/3)x-1
Slope=2/3
So, one has slope=2 and the other has slope=2/3. They’re not parallel because slopes are not the same. They’re not perpendicular because the slopes are not opposites. They’re not equal because their equations are not the same. So, none of the above.
Trapezoidal is involving averageing the heights
the 4 intervals are
[0,4] and [4,7.2] and [7.2,8.6] and [8.6,9]
the area of each trapezoid is (v(t1)+v(t2))/2 times width
for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8
2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24
3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75
4th
average betwen 1.5 and 2 is 1.75
width is 0.4
0.4 times 1.74=0.7
add them all up
0.8+2.24+1.75+0.7=5.49
5.49
t=time
v(t)=speed
so the area under the curve is distance
covered 5.49 meters
Answer:
67.59
Step-by-step explanation:
12x0.80=9.60, 9.60x6=57.6, 57.6+9.99=67.59
