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JulijaS [17]
3 years ago
13

A) Simplify e® * e^ b) Simplify (4ab) c) Simplify 36n'p 9np

Mathematics
2 answers:
timofeeve [1]3 years ago
6 0

a) e^5 * e^4 = e^(5+4) = e^9

b) (4ab^2)^3 = 4^3 * a^3 *b^6 = 64a^3b^6

c) (36n^7p^5)/(9n^4p) = 4n^3p^4

Vladimir [108]3 years ago
5 0

Answer:

a)e^9

b)64a^3b^6

c)4n^3p^4

I hope It helps you have a good day.

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What is the determinant of the coefficient matrix of the system {4x+3y+2z=0 -3x+y+5z=0 -x-4y+3z=0
slava [35]

Answer:

  130

Step-by-step explanation:

You want the determinant of the matrix ...

  \left[\begin{array}{ccc}4&3&2\\-3&1&5\\-1&-4&3\end{array}\right]

One way to figure it is as the difference between the sum of products of the down-diagonals and the sum of products of the up-diagonals:

  D = (4)(1)(3) +(3)(5)(-1) +(2)(-3)(-4) -(-1)(1)(2) -(-4)(5)(4) -(3)(-3)(3)

  = 12 -15 +24 +2 +80 +27

  D = 130

The determinant of the coefficient matrix is 130.

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Many scientific and graphing calculators and web sites can perform this calculation for you.

7 0
3 years ago
Which name accurately describes the figure shown below and why?
mamaluj [8]

Answer: its A

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
This question has three parts. Answer the parts in order.
nalin [4]

Answer:

The area of the smallest section is A_{1}=100yd^{2}

The area of the largest section is A_{2}=625yd^{2}

The area of the remaining section is A_{3}=250yd^{2}

Step-by-step explanation:

Please see the picture below.

1. First we are going to name the side of the larger square as x.

As the third section shares a side with the larger square and the four sides of a square are equal, we have the following:

- Area of the first section:

A_{1}=10yd*10yd

A_{1}=100yd^{2}

- Area of the second section:

A_{2}=x^{2} (Eq.1)

- Area of the third section:

A_{3}=width*length

A_{3}=10yd*x (Eq.2)

2. The problem says that the total area of the enclosed field is 975 square yards, and looking at the picture below, we have:

A_{1}+A_{2}+A_{3}=975yd^{2}

Replacing values:

100+x^{2}+10x=975

Solving for x:

x^{2}+10x-875=0

x=\frac{-10+\sqrt{100+(4*875)}}{2}

x=\frac{-10+\sqrt{3600}}{2}

x=\frac{-10+60}{2}

x=25

3. Replacing the value of x in Eq.1 and Eq.2:

- From Eq.1:

A_{2}=25^{2}

A_{2}=625yd^{2}

- From Eq.2:

A_{3}=10*25

A_{3}=250yd^{2}

3 0
2 years ago
Divide. 71 ÷ 6 Enter your answer by filling in the boxes. __R__
Andru [333]
Possible answer: 11r8?
3 0
2 years ago
Read 2 more answers
Can you please help me solve this?
oee [108]
So, i would use the add the two equation method, so add those to get:
2e=-4
e=-2
then plug in e to get d, so d+-2=1
d=3
plug into the other one to make sure
-3+-2=-5
so it would be (3,-2)
8 0
3 years ago
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