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3 years ago

If f(x) = 7x − 1, what does f(12) represent?

Mathematics

1 answer:

olga2289 [7]3 years ago

8 0

I think it is D, too. Did you submit the test yet?

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Classify number as integer or not. -7/1

miskamm [114]

Answer:

the fraction (-7/1) would be an integer

Step-by-step explanation:

cuz the number is rly -7 which is a whole number which is an integer

8 0

3 years ago

Find the perimeter of triangle ABC.

Harlamova29_29 [7]

By definition, the perimeter of the triangle is the sum of its sides.
We must then use the formula of distance between points:
$d = \sqrt{(x2-x1) ^ 2 + (y2-y1) ^ 2}$
We now look for the longitus for each of the sides:

For L1:
$L1 = \sqrt{(6-2)^2 + (6-2)^2}$
$L1 = \sqrt{32} 
$
$L1 = 4\sqrt{2}$

For L2:
$L2 = \sqrt{(7-2)^2 + (-3-2)^2}$
$L2 = \sqrt{50}$
$L2 = 5\sqrt{2}$

For L3:
$L3 = \sqrt{(7-6)^2 + (-3-6)^2}$
$L3 = \sqrt{82}$

Then, the perimeter is given by:
P = L1 + L2 + L3
Substituting values we have:
$P = 4\sqrt{2} + 5\sqrt{2} + \sqrt{82} 

P = 9\sqrt{2} + \sqrt{82}$

Answer:
the perimeter of triangle ABC is:
none of the above.

5 0

3 years ago

Read 2 more answers

How do you do this question?

Lena [83]

Step-by-step explanation:

The Taylor series expansion is:

Tₙ(x) = ∑ f⁽ⁿ⁾(a) (x − a)ⁿ / n!

f(x) = 1/x, a = 4, and n = 3.

First, find the derivatives.

f⁽⁰⁾(4) = 1/4

f⁽¹⁾(4) = -1/(4)² = -1/16

f⁽²⁾(4) = 2/(4)³ = 1/32

f⁽³⁾(4) = -6/(4)⁴ = -3/128

Therefore:

T₃(x) = 1/4 (x − 4)⁰ / 0! − 1/16 (x − 4)¹ / 1! + 1/32 (x − 4)² / 2! − 3/128 (x − 4)³ / 3!

T₃(x) = 1/4 − 1/16 (x − 4) + 1/64 (x − 4)² − 1/256 (x − 4)³

f(x) = 1/x has a vertical asymptote at x=0 and a horizontal asymptote at y=0. So we can eliminate the top left option. That leaves the other three options, where f(x) is the blue line.

Now we have to determine which green line is T₃(x). The simplest way is to notice that f(x) and T₃(x) intersect at x=4 (which makes sense, since T₃(x) is the Taylor series centered at x=4).

The bottom right graph is the only correct option.

3 0

3 years ago

Determine the sum of the arithmetic series: 5+18 +31 +44 + ... 161.

Finger [1]

Answer:

1079

Step-by-step explanation:

Hello,

18-5 = 13

31-18=13

44-31=13

161=5+13*12

So we need to compute

$\displaystyle \sum_{k=0}^{k=12} \ {(5+13k)}\\\\=\sum_{k=0}^{k=12} \ {(5)} + 13\sum_{k=1}^{k=12} \ {(k)}\\\\=13*5+13*\dfrac{12*13}{2}\\\\=65+13*13*6\\\\=65+1014\\\\=1079$

Thanks

3 0

3 years ago

What is the standard form for the graph?

Novosadov [1.4K]

Y=-2x+0 reason: rise over run as you can see in the graph -2 rise (drop) and -1 run and b=0 y intercept

3 0

3 years ago