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3 years ago

Easy i neeed help!!!!!!

Mathematics

1 answer:

ivann1987 [24]3 years ago

5 0

Answer:

For #3 it is 7/56

Step-by-step explanation:

Multiply 7/8 by 7!

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Lisa can run a mile in 7 minutes. At the rate of speed, how long would it take her to run two kilometers explain pls!!

velikii [3]

If she ran 2 kilometers , isnt it 8 minutes ?

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3 years ago

Read 2 more answers

Given the following exponential function, identify whether the change represents growth or decay, and determine the percentage r

saw5 [17]

Using exponential function concepts, it is found that it represents a decay of 0.9%.

<h3>What is an exponential function?</h3>

A decaying exponential function is <em>modeled </em>by:

$A(t) = A(0)(1 - r)^t$

In which:

A(0) is the initial value.

r is the decay rate, as a decimal.

In this problem, the function is:

$A(t) = 9300(0.991)^{6t}$

Hence:

$1 - r = 0.991$

$r = 0.009$

Thus, it represents a decay of 0.9%.

You can learn more about exponential function concepts at brainly.com/question/25537936

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3 years ago

A cylinder has volume 72pi and radius 3. What is its height?

kifflom [539]

Answer:

Step-by-step explanation:

5 0

3 years ago

Prove each statement that is true and ﬁnd a counterexample for each statement that is false. Assume all sets are subsets of a un

tekilochka [14]

Answer with Step-by-step explanation:

We are given that A, B and C are subsets of universal set U.

We have to prove that

$A\cap (B-C)=(A\cap B)-(A\cap C)$

Proof:

Let x $\in A\cap (B-C)$

Then $x\in A$ and $x\in(B-C)$

When $x\in ( B-C)$ then $x\in B$ but $x\notin C$

Therefore, $x\in( A\cap B)$ but $x\notin (A\cap C)$

Hence, it is true.

Conversely , Let $x\in(A\cap B)$ but $x\notin(A\cap C)$

Then $x\in A$ and $x\in B$

When $x\notin ( A\cap C)$ then $x\notin C$

Therefor, $x\in A\cap (B-C)$

Hence, the statement is true.

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3 years ago

Dhruv is at a car dealership. He is going to randomly select a vehicle to test drive. There are

andrew-mc [135]

Answer:

P(compact cars) = 4/25

Step-by-step explanation:

We know that there are 13 trucks, 8 vans, and 4 compact cars.

Let P denotes the probability of an event

Now we are asked to find the probability of compact cars

Number of favorable events = number of compact cars = 4

total number of outcomes = 13+8+4 = 25

hence, P(compact cars) = number of favorable events/total outcomes

=4/25

8 0

2 years ago