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3 years ago

Jeff ran 2 miles in 12 minutes. Ju Chan ran 3 miles in 18 minutes. Did Jeff and Ju Chan run the same number of miles per minute?

Mathematics

2 answers:

kenny6666 [7]3 years ago

4 0

12/2=6mpm 18/3=6mpm yes they ran at the same rate

klio [65]3 years ago

4 0

Yes they did .

I would use this proportion
2/x 12/1
2 times 1= 2
2 divided by 12=.16

3/x 18/1
3 times 1=3
3 divided by 18=.16

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2 years ago

Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.

lyudmila [28]

Answer:

$-\frac{21}{2}$

Step-by-step explanation:

We can solve this system just by summing each side of the equation:

So, both left sides will be sum, and both right sides too.

The resulting expression will be:

$(3-y)+(3-y) = 6+21$

Ordering and solving both sides:

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3 years ago

The rectangle has length 8 cm and area 48 cm2.

marishachu [46]

Step-by-step explanation:

Given,

length of rectangle(l)= 8cm

area of rectangle(A) = 48cm2

breadth of rectangle(b) = ?

Perimeter of rectangle (P)=?

We know ,

Area of rectangle(A) = l×b

or, 48cm2 = 8cm×b

or, 48cm2 = 8bcm

or, 48cm2/8cm = b

or, 6cm = b

or, b = 6cm

therefore, b = 6cm

Perimeter of rectangle (P) = 2(l+b)

= 2(8cm+6cm)

= 2×14cm

= 28cm

therefore, Perimeter of rectangle(P) = 28cm

Now,

According to the question,

Perimeter of rectangle(P) = Perimeter of square(P)

So,

Perimeter of square(P) = 28cm

length of square(l) = ?

Area of square (A) = ?

We know,

Perimeter of square (P) = 4l

or, 28cm = 4l

or, 28cm/4 = l

or, 7cm = l

or, l = 7cm

therefore, l = 7cm

Now,

Area of square (A) = l^2

= (7cm)^2

= 7cm×7cm

= 49cm^2

therefore, area of square (A)= 49cm^2

3 0

2 years ago

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Lorico [155]

Answer:

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