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3 years ago

How can injection attacks be prevented? Check all that apply

Computers and Technology

2 answers:

bonufazy [111]3 years ago

6 0

If one of the answers is "input validation" and "Data sanitization" it's those two.

V125BC [204]3 years ago

3 0

What are the answer choices?

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A(n) ________ moves over the spinning platters to retrieve data from the hard disk.

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<span>read/write heads should be the answer (:</span>

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3 years ago

Who is willam afton from five nights at freddy

diamong [38]

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3 years ago

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A technician wants to limit access to a group of folders and is using Group Policy to prevent the users in the sales department

Mashcka [7]

Answer:

d. The technician should be setting NTFS permissions instead of using Group Policy.

Explanation:

NTFS (New Technology File System) permissions run on drives formatted with NTFS.Under NTFS permissions, individual users are granted permission at the Windows logon and so in this way local users and network users are affected, affecting each user from wherever he may be connecting from. In the example above using NTFS permissions would solve the problem of file system among departments .

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3 years ago

What else needs to be done when creating a site?

SSSSS [86.1K]

When you are creating a website, you will usually need to add details to the website. If you're coding a website as HTML, you always have to make sure your code is correct. If one thing is a mess up, you have to start the whole thing all over again.

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3 years ago

The instruction format of a computer is given by one indirect bit, opcode bits, register address bits, immediate operand bits an

oksian1 [2.3K]

Answer:

Following are the answer to this question:

Explanation:

The memory size is 1 Giga Bytes which is equal to $2^{30}$

$\texttt{Number of address bits \ \ \ \ \ \ \ \ \ \ \ \ \ \ Number of addresses}\\\\ \ \ \ \ 30 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2^{30}= 1073741824$

B) $\texttt{I \ \ \ Opcode \ \ \ Register address \ \ \ Immediate operand \ \ \ Memory address}\\\\\\\textt{1 \ bit \ \ \ \ \ \ 128 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2 \ bits \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 24 \ bits \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 30 \ bits}\\\\\\$ $= 2^7 \\\\ = 7 \ bits$

calculating the register Bits:

$= 64-(1+7+24+30)\\\\=64 -62\ \ bits\\\\= 2\ \ bits\\$

Immediate value size while merging the additional benefit with the address field:

$= 2^{24} + 2^{30}\\\\= 2^{54}\\\\$ $\texttt{Range before combining(-,+) 24 bits \ \ \ \ \ \ Range after combining( -,+)54bits}\\\\$ $\textt{-2^{12} from + (2^{12}-1) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ -2^{27} from + (2^{27}- 1)}$

$= \frac{24}{2} = 12\\\\= \frac{54}{2} = 27$

The range is accomplished by dividing the bits by 2 into the two sides of the o and the number is one short to 0.

8 0

3 years ago