Answer:
#required generator function
def count_seq():
#starting with number 2. using string instead of integers for easy manipulation
n='2'
#looping indefinitely
while True:
#yielding the integer value of current n
yield int(n)
#initializing an empty string
next_value=''
#looping until n is an empty string
while len(n)>0:
#extracting first digit (as char)
first=n[0]
#consecutive count of this digit
count=0
#looping as long as n is non empty and first digit of n is same as first
while len(n)>0 and n[0]==first:
#incrementing count
count+=1
#removing first digit from n
n=n[1:]
#now appending count and first digit to next_value
next_value+='{}{}'.format(count,first)
#replacing n with next_value
n=next_value
#testing, remove if you don't need this
if __name__ == '__main__':
#creating a generator from count_seq()
gen=count_seq()
#looping for 10 times, printing next value
for i in range(10):
print(next(gen))
Explanation:
