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Jobisdone [24]
3 years ago
8

Please help with the question attached, will mark brainliest!!!!!!!!!!!

Mathematics
1 answer:
UkoKoshka [18]3 years ago
7 0

12; 4

66; 33.4

32.6

respectively in the blanks

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Số táo của An, Bình, Chi là như nhau. An cho đi 17 quả , Chi cho đi 19 quả thì lúc này số táo của Chi gấp 5 lần tổng số táo còn
soldier1979 [14.2K]

Answer:

So, the initial number of apples is 7.

Step-by-step explanation:

The number of apples of An, Binh, and Chi are the same. An gave away 17 apples, Chi gave away 19 apples, so now Chi's apples are 5 times higher than the total remaining apples of An and Binh. How many apples did each of you have at first? (Solve the above problem by equation or system of equations)

Let the initial numbers of apples is a.

An gave 17 apples

Chi gave 19 apples

So,

x - 19 = 5 (x - 17 + x)

x - 19 = 5 (2x - 17)

x - 19 = 10 x - 85

9 x = 66

x = 7

6 0
3 years ago
the temperature in winter night was -23 degrees Fahrenheit the temperature Rose by 5° when the sun rose when the sunset again th
expeople1 [14]

So we have -23 degrees to start

Then add 5 to it

It becomes -23+5=-18

Now subtract 7 from that so -18-7=-25 degrees

Hope this helps

8 0
3 years ago
The 25 members of the Reading Club are buying a book to discuss at the next meeting. The club leader got a special price; the bo
monitta
25 times 8.14 is $203.50 so there’s your answer
4 0
3 years ago
Which set of data represents a linear function?
AVprozaik [17]
The answer is d because the x value does not repeat. Hopes this helps.
5 0
3 years ago
Read 2 more answers
How do you solve this
AlladinOne [14]

Answer:

  • domain: all terms are defined for <em>all real numbers</em>
  • solution: x = 6

Step-by-step explanation:

Rewrite the equation as a single exponential. After taking the log, the solution becomes obvious.

5^{x-2}-7^{x-3}=7^{x-5}+11\cdot 5^{x-4}\\\\5^{x-2}-11\cdot 5^{x-4}=7^{x-3}+7^{x-5}\\\\5^{x-2}(1-11\cdot 5^{-2})=7^{x-3}(1+7^{-2})\\\\5^{x-2}\dfrac{14}{25}=7^{x-3}\dfrac{50}{49}\\\\1=\dfrac{2\cdot 7^{x-3}5^4}{2\cdot 5^{x-2}7^3}=\left(\dfrac{7}{5}\right)^{x-6}\\\\0=(x-6)\log(1.4)\\\\x=6

6 0
3 years ago
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