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PolarNik [594]
3 years ago
7

Can you answer that but simply make it look it easy

Mathematics
1 answer:
mote1985 [20]3 years ago
4 0

Answer:

15, 6.4, 13

Step-by-step explanation:

That is the most simple way I could answer it for you.

<u><em>PLEASE MARK BRAINLIEST</em></u>

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C2 = 39<br><br> (c squared) <br><br> please help :(
iVinArrow [24]

<em>Answer:</em>

<em></em>\boxed{c = \sqrt{39} / c= - \sqrt{39} }<em></em>

<em>This " / " means or, btw!</em>

<em>Step-by-step explanation:</em>

<em></em>c^2 = 39<em></em>

<em>⇒Take square root.</em>

<em></em>c =<em> ± </em>\sqrt{39}<em></em>

<em></em>c = \sqrt{39}<em> or </em>c = -\sqrt{39}<em></em>

<em>Hope this helped you!</em>

7 0
3 years ago
Plz help with this problem!<br><br> x^4 + x^2 + 1
TEA [102]

Answer:

You cannot simplify this problem down anymore; it is at its simplest form.

Step-by-step explanation:

You cannot add together x^4 and x^2 due to the simple fact that they do not share similar exponents.

For example you could add together x^4 and x^4 to get 2x^4. But you cannot add x^4 and x^2.

7 0
3 years ago
Given the following functions f(x) and g(x), solve (f + g)(5) and select the correct answer below: f(x)=2x^2-10 g(x)=x+9
steposvetlana [31]

Answer:

\large\boxed{(f+g)(5)=54}

Step-by-step explanation:

f(x)=2x^2-10,\ g(x)=x+9\\\\(f+g)(x)=f(x)+g(x)\\\\\text{Substitute:}\\\\(f+g)(x)=(2x^2-10)+(x+9)=2x^2-10+x+9=2x^2+x+(-10+9)\\\\(f+g)(x)=2x^2+x-1\\\\(f+g)(x)(5)\to\text{put x = 5 to the equation of the function:}\\\\(f+g)(5)=2(5^2)+5-1=2(25)+5-1=50+5-1=54

8 0
3 years ago
If angle KLJ~angle VWU. Find the x value
Alenkasestr [34]

Answer:

17

Step-by-step explanation:

Since angle KLJ~angle VWU are similar :

KL / WV = KJ/ UV

(25 / 20) = (4x - 23 / 2x + 2)

Cross multiply :

25(2x + 2) = 20(4x - 23)

50x + 50 = 80x - 460

50x - 80x = - 460 - 50

-30x = -510

x = 510 / 30

x = 17

5 0
3 years ago
The temperature dropped from 75 degrees to 50 degrees
enot [183]

Answer:

50%

Step-by-step explanation:

sorry I don't have an explanation...

3 0
2 years ago
Read 2 more answers
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