Una librería consta de 5400 libros repartidos en 3 estanterías

Mathematics

1 answer:

pishuonlain [190]3 years ago

7 0

Answer:

B = 900 Libros

A = 2700 Libros

C = 1800 Libros

Step-by-step explanation:

A = 3B

2B = C

A + B + C = 5400

3B + B + 2B = 5400

6B = 5400

B = 5400 / 6

B = 900 Libros

A = 3B

A = 3(900)

A = 2700 Libros

C = 2B

C = 2(900)

C = 1800 Libros

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For the matrices below. Find all (real) eigenvalues. <br><br> A= [7 9]<br> [0 9]

Jet001 [13]

Answer:

The answer is "9 and 7".

Step-by-step explanation:

Given:

$A=\left[\begin{array}{cc}7&9\\0&9\end{array}\right]$

Using formula:

$|A-\lambda \cdot I|= 0\\\\$

$\to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]-\lambda \left[\begin{array}{cc}1&0\\0&1\end{array}\right] |=0\\\\\\ \to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]- \left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right] |=0\\\\\\\to|\left[\begin{array}{cc}7-\lambda &9\\0&9-\lambda\end{array}\right]|=0\\\\\\\to|(7-\lambda)(9-\lambda)|=0\\\\\to (7-\lambda)(9-\lambda)=0\\\\\to 7-\lambda=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 9-\lambda=0\\\\$