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bezimeni [28]
3 years ago
12

Help me please I don't understand

Mathematics
1 answer:
Arturiano [62]3 years ago
3 0

Step-by-step explanation:

hope this helps you out with the problems

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Two finite sets have m and n elements . The total no. of subsets of the first set is 56 more than the total no.of subsets in the
lakkis [162]
If some set A has n elements, then it has 2^n subsets. 
Using that, the sentence, "The total number of subsets of ‘m’ is 56 more than the total number of subsets of ‘n’." gives you the equation 2^m - 2^n = 56 
Factor both sides: 2^n * (2^(m-n) - 1) = 2^3 * 7 
Since 2^n is a power of 2 and (2^(m-n) - 1) is an odd integer, we must have 2^n = 2^3 2^(m-n) - 1 = 7 
Solving these, you get n = 3 and m = 6.
5 0
4 years ago
Given the equation: 4+x−15=10
Anni [7]

Answer:

C

Step-by-step explanation:

combine like terms, 4 and -15 = -11

4 0
3 years ago
Read 2 more answers
Proof that the identities are equal to eachother​
Vikentia [17]

Answer:

Hello, hope this will help:)

6 0
3 years ago
(-5/11)h+(7/9)=(2/9) (solve for h) grade lvl. 7
Ivanshal [37]

Answer:

h = 11/9 or 1 2/9

Step-by-step explanation:

(-5/11)h+(7/9)=(2/9)

(-5/11)h=(2/9)-(7/9)

(-5/11)h=(-5/9)

h = (-5/9)(-11/5)

h = 11/9

or

h = 1 2/9


5 0
3 years ago
Find f’(x).<br><br> 1. f(x)=x^2-5x+1<br><br> 2. f(x)=10/x
kompoz [17]

Answer:

1) 2x-5                 2)  -10/x^2

Step-by-step explanation:

Use power rule and constant rule for the first one:

1) f(x)=x^2-5x^1+1                                (x^n)'=nx^(n-1) and (c)'=0

f'(x)=2x^1-5(1)x^0+0                        

f'(x)=2x-5(1)                                        x^0=1

f'(x)=2x-5

Use just power rule for last one after a rewrite

2) f(x)=10/x

f(x)=10x^(-1) now use power rule

f'(x)=-10x^(-2) =-10/x^2

6 0
3 years ago
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