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ELEN [110]
1 year ago
7

Find the 17 th term of each sequence. a₁₆ = 1/5, d= 1/2

Mathematics
1 answer:
Dmitry [639]1 year ago
3 0

7/10 is 17th term of sequence a₁₆ = 1/5, d= 1/2.

Given the 16th term and the common difference, we add the common difference from the 16th term to determine the 17th term:

a₁₇ =  a₁₆ + d

    =  1/5 + 1/2

    = 7/10

<h3>How to solve an equation?</h3>

To solve linear equations, utilize the steps that are provided below.

  1. Remove parentheses from each side of the equation and combine similar terms to make it simpler.
  2. To separate the variable term on one side of the equation, use addition or subtraction.
  3. To find the variable, use division or multiplication.
  4. The common denominator can be multiplied by each side of the equation to eliminate fractions.

Lets take an example of solve z for 7z – (3z – 4) = 12

Here is no multiplication or division, so this will be easy to solve

⇒ 7z – (3z – 4) = 12

⇒ 7z – 3z + 4 = 12

⇒ 4z = 12 – 4

⇒ 4z = 8

⇒ z = 8/4

⇒ z = 2

See, that was so simple, using the mentioned methods, every linear equation can be solved easily.

Learn more about  linear equations

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What is the surface area of this triangular prism rounded to the nearest tenth? A) 48.6km2 B) 63.4 km2 C) 72.6 km2 D) 84.4 km2
Mekhanik [1.2K]

Correct option B)63.4km^2 .

<u>Step-by-step explanation:</u>

We have the following figure attached as shown below.

Now, this triangular prism have 2 similar right angled surfaces and 3 rectangular surfaces , Let's calculate area for all of them:

2 similar right angled surfaces

We know that area of triangle = \frac{1}{2} b(h)

⇒ area = \frac{1}{2} b(h)

⇒ area = \frac{1}{2} (3.6)(7.7)

⇒ area = 13.86km^{2}

But there 2 such surfaces so , area = 2(13.86) = 27.72km^2

3 rectangular surfaces

Area of rectangle = length(breadth)

⇒ area_1 = 3.6(1.8)

⇒ area_1 = 6.48km^2

⇒ area_2= 7.7(1.8)

⇒ area_2 = 13.86km^2

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Area = 27.72+35.64 = 63.36km^2 = 63.4km^2

Correct option B)63.4km^2 .

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The domain of the function that is plotted on the graph ranges from 0, 1, 2 to 9.

1, 2, 3 to 9 are all integers. Therefore, we can conclude that the "domain is all integers 0 through 9."

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