Answer:
2x³+3x²-8x+3
Step-by-step explanation:
So we know x=½,x=1 and x=-3
Then (2x-1)(x-1)(x+3) are the factors
(2x-1)[(x²+3x-x-3)]
(2x-1)[(x²+2x-3)]
2x³+4x²-6x-x²-2x+3
2x³+3x²-8x+3
Answer:
Step-by-step explanation:
-2x + 3y = 6.....(x, -4)...so y = -4
-2x + 3(-4) = 6
-2x - 12 = 6
-2x = 6 + 12
-2x = 18
x = -18/2
x = -9
so the value of x is -9.....(-9,-4)
We solve the inequality by subtracting 56.50 from both sides of the equation,
10.45b + 56.50 - 56.50 < 292.67 - 56.50
10.45b < 236.17
Then, divide both sides of the inequality by 10.45
b < 22.6
The solution suggests that the number of boxes than can be loaded on a truck without exceeding the weight limit of the truck should always be lesser than 22.6. Since we are talking about number of boxes, the maximum number of boxes that can be loaded should only be 22.
I hope you can see it just try to zoom in
What you have to do is add them all!
20 bar
11.4 2 11.4 weights
11.4
4.5 2 4.5 weights
4.5
450.0 4 450 weights
450.0
450.0
+450.0
---------
1.8
10
200
+1,600
--------------
1,811.8 is the answer
