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2 years ago

What would be the second step in solving the equation y−16=3y?

Mathematics

2 answers:

Leya [2.2K]2 years ago

6 0

Answer:

divide both sides by 2

Step-by-step explanation:

becoz first step is move the numbers

pliz give a brainliest

stiv31 [10]2 years ago

3 0

Answer:

Divide both sides by 4

Step-by-step explanation:

Please give brainliest

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4 0

3 years ago

Given sin(−θ)=−1/6 and tanθ=−√35/35 What is the value of cosθ?

murzikaleks [220]

Answer:

$cos(\theta)=-\frac{\sqrt{35} }{6}$

Step-by-step explanation:

Recall the negative angle identity for the sine function:

$sin(- \theta)=-sin(\theta)$

Then, we can find the value of $sin(\theta)$ :

$sin(\theta)=-sin(-\theta)\\sin(\theta) =-(-\frac{1}{6} )\\sin(\theta)= \frac{1}{6}$

Now recall the definition of the tangent function:

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

Therefore, now that we know the value of $sin(\theta)$ , we can solve in this equation for $cos(\theta)$

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}\\-\frac{\sqrt{35} }{35} =\frac{1/6}{cos(\theta)} \\cos(\theta)=-\frac{\frac{1}{6} }{\frac{\sqrt{35} }{35} } \\cos(\theta)=-\frac{35}{6\,\sqrt{35} } \\cos(\theta)=-\frac{\sqrt{35} }{6}$

5 0

2 years ago

Drake's sister Stephanie is 2 years younger than him. If the sum of Drake's age and 2 times Stephanie's age is 98, how old is St

Bogdan [553]

Answer:

S=32 D=34

Step-by-step explanation:

{-----------------VARIABLES------------}

D=Drake

S=Stephanie

TA=Total Age

{----------------GIVEN/EQUATIONS-------------}

D=S+2

TA=D+2s

{--------------SUB/SOLVE---------------}

98=D+2S

SUB FOR D

98=3S+2

96=3S

S=32

D=S+2

D=34

5 0

2 years ago

Subtract using a number line. 12−(−5) Select the point on the number line to plot the answer.

andreev551 [17]

It 17 but you didn't give me a number line

7 0

3 years ago

Read 2 more answers

6 - 3 ²/⁵ =<br> What is 6 - 3 ²/⁵

Leya [2.2K]

$~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 6-3^{\frac{2}{5}}\implies 6-\sqrt[5]{3^2}\implies 6-\sqrt[5]{9}~~\approx ~~4.8$

3 0

2 years ago