W(2) = 2^2 + 2 = 4 + 2 = 6
u(w(2)) = -x -2 = -6 - 2 = -8
answer: u(w(2)) = -8
The area is that of two 20 yd squares and one 20 yd circle.
.. A = 2*(20 yd)^2 +(π/4)*(20 yd)^2
.. = (2 +π/4)*(400 yd^2)
.. = (800 +100π) yd^2
.. ≈ 1114.16 yd^2
The perimeter is that of a 20 yd circle and 80 yd more.
.. P = π*20 yd + 80 yd
.. ≈ 142.83 yd
Answer:
Step-by-step explanation:
The problem is asking for slope-intercept form, luckily, they gave us both of those things.
Slope-intercept form: 
, where 
slope and 
y-intercept.
So,
Hope this helps!
Answer:
73
Step-by-step explanation:
120-47=73 simple math
