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asambeis [7]
3 years ago
14

Paracelsus University has two kinds of professors: academic professors and professional professors. At Paracelsus University, 60

% of the professors are academic professors, and 70% of the professors are tenured. If 90% of the professors at Paracelsus University are academic professors or tenured or both, then what percent of the professional professors there are tenured?A. 25
B. 37.5
C. 50
D. 62.5
E. 75
Mathematics
1 answer:
Phoenix [80]3 years ago
7 0
I got b that’s what I got
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0.551 as a percent <br><br> Thank you
Bingel [31]

Answer:

55.1%

Step-by-step explanation:

When a number is a percent, then one mutliplies it by 100, because a percent is a way of representing a value out of 100. Therefore, 0.551 as a percent is;

0.551 * 100

55.1%

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Examine the following table. Determine whether the rate of change is constant or variable. If it is constant, state the rate of
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Answer:

Variable rate of change.

Step-by-step explanation:

Plot the points and you'll see that the graph is not a straight line, therefore the rate of change is variable.

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What is the algebraic rule for this statement: "Translate the point right 6
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I think it’s D. (x+6, y-4)
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3 years ago
Help me I need this answer really fast
Juli2301 [7.4K]
Answer is D or the last choice
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3 years ago
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The U.S. Census Bureau conducts a study to determine the time needed to complete the short form. The Bureau surveys 200 people.
NISA [10]

Answer:

8.2-2.58\frac{2.2}{\sqrt{18}}=6.86    

8.2+2.58\frac{2.2}{\sqrt{18}}=9.54    

So on this case the 90% confidence interval would be given by (6.86;9.54)    And the error is given by:

ME= 2.58\frac{2.2}{\sqrt{18}} =1.338

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=8.2 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=2.2 represent the population standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58

Now we have everything in order to replace into formula (1):

8.2-2.58\frac{2.2}{\sqrt{18}}=6.86    

8.2+2.58\frac{2.2}{\sqrt{18}}=9.54    

So on this case the 90% confidence interval would be given by (6.86;9.54)    And the error is given by:

ME= 2.58\frac{2.2}{\sqrt{18}} =1.338

8 0
3 years ago
Read 2 more answers
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