Question

256-x²/4factorise in process​

Answer 1

Answer:

$16^2-(\dfrac{x}{2})^2=(16+\dfrac{x}{2})(16-\dfrac{x}{2})$

Step-by-step explanation:

The given expression is : $256-\dfrac{x^2}{4}$.

We need to factorize it.

We know that, 16² = 256

So,

$256-\dfrac{x^2}{4}=(16)^2-(\dfrac{x}{2})^2$

We know that, $a^2-b^2=(a-b)(a+b)$

$16^2-(\dfrac{x}{2})^2=(16+\dfrac{x}{2})(16-\dfrac{x}{2})$

Hence, this is the required solution.