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aliina [53]
3 years ago
6

suppose that y varies jointly with x and z. Find your when x=3 and z=5 , given that y=72 when x=6 and z=4

Mathematics
1 answer:
Hitman42 [59]3 years ago
3 0
Y α xz

y = kxz             y = 72, when x = 6, and z = 4

72 = k*6*4

72 = k*24

24k = 72

k = 72/24

k = 3.

<span>y = kxz    
</span>
<span>y = 3xz    </span>

Finding y, when x = 3, z = 5.

y = 3xz

y = 3*3*5

y = 45
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2/3*5= 10/3 = 3.33 > 2
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The growth of 100 young trees near a river is given below. At most 50 yards from the river (Event Y) More than 50 yards from the
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It is 91% more likely that the tree was atmost 500 yards from the river.

<h3>Step-by-step explanation:</h3>

We are given with distance and height of 100 young trees near a river.

From that table, in total there are 55 trees which grow more than 3 ft during the year.

And among those 55 trees, 50 trees are atmost 50 yards from river.

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Consider a sample with data values of 27, 24, 21, 16, 30, 33, 28, and 24. Compute the 20th, 25th, 65th, and 75th percentiles. 20
densk [106]

Answer:

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P_{25} = 21.75  --- 25th percentile

P_{65} = 27.85   --- 65th percentile

P_{75} = 29.5   --- 75th percentile

Step-by-step explanation:

Given

27, 24, 21, 16, 30, 33, 28, and 24.

N = 8

First, arrange the data in ascending order:

Arranged data: 16, 21, 24, 24, 27, 28, 30, 33

Solving (a): The 20th percentile

This is calculated as:

P_{20} = 20 * \frac{N +1}{100}

P_{20} = 20 * \frac{8 +1}{100}

P_{20} = 20 * \frac{9}{100}

P_{20} = \frac{20 * 9}{100}

P_{20} = \frac{180}{100}

P_{20} = 1.8th\ item

This is then calculated as:

P_{20} = 1st\ Item +0.8(2nd\ Item - 1st\ Item)

P_{20} = 16 + 0.8*(21 - 16)

P_{20} = 16 + 0.8*5

P_{20} = 16 + 4

P_{20} = 20

Solving (b): The 25th percentile

This is calculated as:

P_{25} = 25 * \frac{N +1}{100}

P_{25} = 25 * \frac{8 +1}{100}

P_{25} = 25 * \frac{9}{100}

P_{25} = \frac{25 * 9}{100}

P_{25} = \frac{225}{100}

P_{25} = 2.25\ th

This is then calculated as:

P_{25} = 2nd\ item + 0.25(3rd\ item-2nd\ item)

P_{25} = 21 + 0.25(24-21)

P_{25} = 21 + 0.25(3)

P_{25} = 21 + 0.75

P_{25} = 21.75

Solving (c): The 65th percentile

This is calculated as:

P_{65} = 65 * \frac{N +1}{100}

P_{65} = 65 * \frac{8 +1}{100}

P_{65} = 65 * \frac{9}{100}

P_{65} = \frac{65 * 9}{100}

P_{65} = \frac{585}{100}

P_{65} = 5.85\th

This is then calculated as:

P_{65} = 5th + 0.85(6th - 5th)

P_{65} = 27 + 0.85(28 - 27)

P_{65} = 27 + 0.85(1)

P_{65} = 27 + 0.85

P_{65} = 27.85

Solving (d): The 75th percentile

This is calculated as:

P_{75} = 75 * \frac{N +1}{100}

P_{75} = 75 * \frac{8 +1}{100}

P_{75} = 75 * \frac{9}{100}

P_{75} = \frac{75 * 9}{100}

P_{75} = \frac{675}{100}

P_{75} = 6.75th

This is then calculated as:

P_{75} = 6th + 0.75(7th - 6th)

P_{75} = 28 + 0.75(30- 28)

P_{75} = 28 + 0.75(2)

P_{75} = 28 + 1.5

P_{75} = 29.5

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3 years ago
A segment with endpoints A(2,6) and C(5,9) is partitioned by a point B such that AB and BC form a 3:1 ratio. Find B​
Aneli [31]

Answer:

The coordinate of point B is (4, 8.25)

Step-by-step explanation:

Here, we want to find the coordinates of point B

To do this, we are to use the section internal division formula as follows;

(x,y) = (nx1 + mx2)/(m + n) , (ny1 + my2)/(m + n)

In this case;

(x1,y1) = (2,6)

(x2,y2) = (5,9)

(m,n) = (3,1)

Substituting these values into the section formula, we have;

(x,y) = (1(1) + 3(5))/(1 + 3) , (1(6) + 3(9))/3 + 1)

(x,y) = (16/4, 33/4)

(x,y) = (4,8.25)

3 0
3 years ago
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