3.75 litres is the volume of the balloon indoors at a temperature of 25°C.
Explanation:
Data given:
initial temperature of the gas in balloon = -35°C or 238.15 K
initial volume = 3 litres
final temperature = 25 °C or 298.15 K
final volume =?
pressure remains constant
From the data given when pressure is constant Charles' law is applied.
= 
Rearranging the equation to know the final volume of the gas in balloon
V2 = 
V2 = 
V2 = 3.75 Litres
when the temperature of a gas is increased and pressure remains constant the volume of the gas increases.
Answer:
Ba(NO₃)₂ (aq) + H₂SO₄ (aq) → BaSO₄ (s) + 2HNO₃ (aq)
Explanation:
The equation bellow can be explained by the dissociation of each specie:
Ba(NO₃)₂ (aq) → Ba²⁺ (aq) + 2NO₃⁻ (aq)
H₂SO₄ (aq) → 2H⁺ (aq) + SO₄²⁻ (aq)
The reaction will lead to the formation of solid barium sulfate and nitric acid.
Answer:
exemples of elements with 1 valence electron: Hydrogen, lithium, potassium.
exemples of elements with 2 valence electrons: magnessium, calcium.
boron has 3 valence electrons. Phosphorus has 5 valence electrons.
carbon has 4 valence electrons.
exemples of elements with 5 valence electrons: Phosphorus, nitrogen
exemples of elements with 7 valence electrons: fluorine, chlorine
exemples of elements with 8 valence electrons: helium, argon
Explanation:
the easiest way to know the number of electrons are by the number of the group so 14 is 4, 16 is 6.
Answer:
1 is B, 2 is B a cold front
Explanation:
In order for a front to form, two air masses have to collide, and for 2 a cold front is represented by a red ljine with half circles
Answer:
The answer to your question is a) N₂ b) 3.04 g of NH₃
Explanation:
Data
mass of H₂ = 2.5 g
mass of N₂ = 2.5 g
molar mass H₂ = 2.02 g
molar mass of N₂ = 28.02 g
molar mass of NH₃ = 17.04 g
Balanced chemical reaction
3H₂ + 1 N₂ ⇒ 2NH₃
A)
Calculate the theoretical yield 3H₂ / N₂ = 3(2.02) / 28.02 = 0.22
Calculate the experimental yield H₂/N₂ = 2.5/2.5 = 1
Conclusion
The limiting reactant is N₂ (nitrogen) because the experimental proportion was higher than the theoretical proportion.
B)
28.02 g of N₂ -------------------- (2 x 17.04) g of NH₃
2.5 g of N₂ -------------------- x
x = (2.5 x 2 x 17.04) / 28.02
x = 85.2 / 28.02
x = 3.04 g of NH₃