C. 10r-3
Because 2r+5=7, the minus 6 and 7 which gives you 1 then minus 4 and 1 witch is 3 then you do 10r-3 and it will get you to 2r+5=7 again. I hope this helped!
3√24 + 2√3(√3-2√18) =
3(√(4*6) + 2√3( √3-2√(2*9)) =
3*2√6 + 2√3 ( √3 - (2*3) √2) =
6√6 + 2√3(√3 - 6√2) =
6√6 + 6 - 12√3*√2 =
6√6 + 6 - 12√(6) =
6 - 6√6 = 6(1-√6)
Answer:
Mason recieved 15 points for answering the question correctly so that means that he had -15 points before. The points would be at -15 and 0.
Answer:
y=4
Step-by-step explanation:
2(y+1)-2=4+y
2y+2-2=4+y
2y=4+y
2y-y=4
y=4
Answer:
C. cot theta
Step-by-step explanation:
(csc theta -cot theta )/(sec theta -1)
csc = 1/ sin
cot = cos / sin
sec = 1 / cos
Let x = theta
(1/ sin x -cos x / sin x )/(1/ cos x -1)
Getting a common denominator in the denominator and combining terms
(1- cos x)/ sinx / ( 1 - cos x) / cos x
(1- cosx) (1- cosx)
----------- ÷ ------------
sinx cos x
Copy dot flip
(1- cosx) cosx
----------- * ------------
sinx 1 -cos x
Cancel like terms
cos x / sin x
cos / sin = cot
cot x
cot theta
