Write an algebraic equation twice a number increased by 10 is 50
1 answer:
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Answer:
The equation has no solutions
Step-by-step explanation:
If we re arrange the equation a little more we will obtain the following
|x|=-11
Which is a contradiction since, the |x| is always a positive number
Attached is the representation of this function y= |x|
It means, that it doesnt matter what value 'x' has, the answer is the same number but, positive
Answer:
option C
c. least: $101
greatest: $1001
Step-by-step explanation:
A radio station advertises a contest with ten cash prizes totaling $5510. There is to be a $100 difference between each successive prize.
Sum of 10 prizes = 5510
100 is the difference. there is a common difference d=100
So its a arithmetic sequence
the sum formula for arithmetic sequence is
Sn = 5510, n=10 n d= 100 we need to find out first term a1
5510 = 5 (2a1 + 900)
5510 = 10a1 + 4500
Subtract 4500 on both sides
1010= 10a1
divide by 10 on both sides
a1 = 101
so first term that is least term is 101
To find out greatest term we use formula
a(10) = 101 + (10-1)100
= 101 + 900= 1001
greatest is 1001