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BARSIC [14]
3 years ago
5

-6x +7 for x = -6 I don’t understand

Mathematics
1 answer:
galina1969 [7]3 years ago
3 0

Step-by-step explanation:

put x = -6 in the equation.

= -6 ( -6). + 7 =. 36 + 7 = 43

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The graph below shows the function f(x)=x-3/x^2-2x-3 which statement is true
Ugo [173]

Answer:

The correct option is A.

Step-by-step explanation:

Domain:

The expression in the denominator is x^2-2x-3

x² - 2x-3 ≠0

-3 = +1 -4

(x²-2x+1)-4 ≠0

(x²-2x+1)=(x-1)²

(x-1)² - (2)² ≠0

∴a²-b² =(a-b)(a+b)

(x-1-2)(x-1+2) ≠0

(x-3)(x+1) ≠0

x≠3 for all x≠ -1

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Asymptote:

x-3/x^2-2x-3

We know that denominator is equal to (x-3)(x+1)

x-3/(x-3)(x+1)

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1/x+1

We have asymptote at x=-1 and hole at x=3, therefore the correct option is A....

4 0
3 years ago
Read 2 more answers
Write the equation g(x) in vertex form of a
DerKrebs [107]

The equation g(x) in vertex form of a  quadratic function for the transformations  whose graph is a  translation 4 units left and 1 unit up of the  graph of f(x) is (x-4)² + 1

Given a  quadratic function for the transformations given  the function f(x) = x²

If the function g(x) of the graph is translated 4 units to the left, the equation becomes (x-4)² (note that we subtracted 4 from the x value

  • Translating the graph 1 unit up will give the final function g(x) as (x-4)² + 1 (We added 1 since it is an upward translation.)

Hence the equation g(x) in vertex form of a  quadratic function for the transformations  whose graph is a  translation 4 units left and 1 unit up of the  graph of f(x) is (x-4)² + 1

Learn more here: brainly.com/question/15381183

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2 years ago
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Answer:

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Step-by-step explanation:

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