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3 years ago

Please help asap Will mark brainliest

Mathematics

1 answer:

statuscvo [17]3 years ago

4 0

Answer:

(4,-4)

Step-by-step explanation:

(x,y)

y=3/4x - 7

y=3/4*(4)-7

y=3-7

y=-4

(4,-4)

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Subtract 7x-9 from 2x^2-11 A) 2x^2-7x-2 B) 2x^2+7x-20 C) 2x^2+7x-2

Natali [406]

We keep the 2x^2 because we can only subtract something from that if it also is squared. From there, we subtract the 7x from 2x^2-11. Since there is no previous x's in the 2x^2-11, we just make it -7x. So, without even continuing the problem, we see that A) is the correct answer because it is the only one with -7x.

5 0

3 years ago

Read 2 more answers

Select all the rates that are unit rates.

Nataly_w [17]

Answer:

$\frac{2/3}{1}$ and $\frac{3}{1}$

Step-by-step explanation:

Options

$\frac{1}{1/3}$ $\frac{2/3}{1}$ $\frac{2}{3}$ $\frac{3}{1}$ $\frac{1}{9}$

Required

Select the unit rates

Unit rate involve two items where the first item being measured can be any positive number, but the second item must be measured in units (i.e. 1)

For clarity:

If $\frac{a}{b}$ represents unit rate, then $b = 1$

Having said that:

Only $\frac{2/3}{1}$ and $\frac{3}{1}$ satisfy the condition of unit rates; others are not because they have a denominator other than 1

3 0

3 years ago

Solve the System by Graphing:

Marat540 [252]

Answer:

B) One solution
The solution is (2, -2)
The graph is below.

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Explanation:

I used GeoGebra to graph the two lines. Desmos is another free tool you can use. There are other graphing calculators out there to choose from as well.

Once you have the two lines graphed, notice that they cross at (2, -2) which is where the solution is located. This point is on both lines, so it satisfies both equations simultaneously. There's only one such intersection point, so there's only one solution.

--------

To graph these equations by hand, plug in various x values to find corresponding y values. For instance, if you plugged in x = 0 into the first equation, then,

y = (-3/2)x+1

y = (-3/2)*0+1

y = 1

The point (0,1) is on the first line. The point (2,-2) is also on this line. Draw a straight line through the two points to finish that equation. The other equation is handled in a similar fashion.