It either B or D. zoz dnd keep
Step-by-step explanation:
Let y1 and y2 be (e^x)/2, and (xe^x)/2 respectively.
The Wronskian of them functions be
W = (y1y2' - y1'y2)
y1 = (e^x)/2 = y1'
y2 = (xe^x)/2
y2' = (1/2)(x + 1)e^x
W = (1/4)(x + 1)e^(2x) - (1/4)xe^(2x)
= (1/4)(x + 1 - x)e^(2x)
W = (1/4)e^(2x)
Since the Wronskian ≠ 0, we conclude that functions are linearly independent, and hence, form a set of fundamental solutions.
This requires 2 pints of oil.
Using a proportion to solve this, we have:

Cross multiplying, we have
1/2*10 = (2 1/2)*x
5 = (2 1/2)x
Divide both sides by 2 1/2:
5÷(2 1/2) = (2 1/2)x÷(2 1/2)
2 = x
It would be c because that is what goes