The circumferince of the circle is 2πR ;
The area of the circle is π
![R^{2}](https://tex.z-dn.net/?f=%20R%5E%7B2%7D%20)
;
Then, 2πR = 704 ;
R = 352 / π ;
π
![R^{2}](https://tex.z-dn.net/?f=%20R%5E%7B2%7D%20)
= π × ( 352 / π )^2 = ( 352^2) / π = 123904 / π ≈ 39459.87 ≈ 39460 cm^2 ;
Answer: 9 is mean and median is 6
Step-by-step explanation:
Answer:
![\tan(51°) = \frac{10}{x} \\x = \frac{10}{ \tan(51°) } \\ x = \frac{10}{1.235} \\ \boxed{ x = 8.1}](https://tex.z-dn.net/?f=%20%5Ctan%2851%C2%B0%29%20%20%3D%20%20%5Cfrac%7B10%7D%7Bx%7D%20%20%5C%5Cx%20%3D%20%20%5Cfrac%7B10%7D%7B%20%5Ctan%2851%C2%B0%29%20%7D%20%20%5C%5C%20x%20%3D%20%5Cfrac%7B10%7D%7B1.235%7D%20%20%5C%5C%20%5Cboxed%7B%20x%20%3D%208.1%7D)
<h3>★ Value of x is <u>8.1</u>.</h3>
![\sin(51°)= \frac{10}{H} \\ h = \frac{10}{ \sin(51°) } \\ H= \frac{10}{0.777} \\ \boxed{H= 12.8676}](https://tex.z-dn.net/?f=%20%5Csin%2851%C2%B0%29%3D%20%20%5Cfrac%7B10%7D%7BH%7D%20%20%5C%5C%20h%20%3D%20%20%5Cfrac%7B10%7D%7B%20%5Csin%2851%C2%B0%29%20%7D%20%20%5C%5C%20H%3D%20%20%5Cfrac%7B10%7D%7B0.777%7D%20%20%5C%5C%20%20%5Cboxed%7BH%3D%2012.8676%7D)
<h3>★ Value of H is <u>12.8676</u>.</h3>
Remember:
- tan∅=Perpendicular/Base
- sin∅=Perpendicular/Hypotenuse
The Sample Space for the experiment is {B, W, R, G, P}. :) The answer to the second question is 7/12.
Hope this helps!
Answer:
x = -1
Step-by-step explanation:
3(x+2)=−5−2(x−3) multiply 3 and -2 with inside the parenthesis
3x + 6 = -5 -2x + 6 now add the like terms
3x + 2x = 1 - 6
5x = -5 simplify both sides
x = -1