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professor190 [17]
3 years ago
10

I can’t download anything so if anyone can find a way to help with this I’d be grateful (^_^)

Mathematics
1 answer:
zaharov [31]3 years ago
7 0
It's hard to explain by words so sorry if you don't understand. For the graphing part, starting from (-3, 0), plot points in (1, 2), (6, 3), and connect them. The end of a line should be (10, 3.5). You will understand better if you use graphing calculator.

The answer of a second question is {x|x is greater or equal to -3.
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Solve y + 4 > - 2.2. Check your solution.
maks197457 [2]
Pretty sure its y > -6.2
This is because you subtract 4 from both sides and get y > -6.2
Please correct me if im wrong thx!
6 0
3 years ago
Read 2 more answers
Need help in this mathquestion. The function h(x)=(x+2)^2 can be expressed in the form f(g(x)) where f(x)=x^2 , and g(x) is defi
blsea [12.9K]

Answer:

In a nutshell, g(x) = x+2.

Step-by-step explanation:

A composition is operation between function that consist in replacing the independent variable of the first function, f(x) in this case, for g(x). Common notations for composition between functions are f(g(x)) and f\circ g (x). If we know that h(x) = f\circ g (x) = (x+2)^{2} and f(x) = x^{2}, then g(x) = x+2.

In a nutshell, g(x) = x+2.

4 0
3 years ago
PLEASE HELP ME I CAN'T GET THIS WRONG, I KNOW ITS NOT #4
Nina [5.8K]
H(x) = 0.15x - 0.19
p(x) = 0.29x - 0.16

(p · h)(-8) = (0.29(-8) - 0.16)(0.15(-8) - 0.19)
(p · h)(-8) = (-2.32 - 0.16)(-1.2 - 0.19)
(p · h)(-8) = (-2.48)(-1.39)
(p · h)(-8) = 3.4472

It is approximately equal to 3.
5 0
3 years ago
What is the lowest denominator of 1/8?
MissTica
The lowest possible denominator of 1/8 is 1/8.

1/8 can't be simplified anymore making this the smallest possible denominator.

3 0
3 years ago
Read 2 more answers
Given the function h(x) =1/3 |x-6| +4, evaluate the function when x = - 3, - 2, and 0
Masja [62]

|x| = x for x ≥ 0

examples:

|3| = 3; |0.56| = 0.56; |102| = 102

|x| = -x for x < 0

examples:

|-3| = -(-3) = 3; |-0.56| = -(-0.56) = 0.56; |-102| = 102

--------------------------------------------------------------------------------

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

--------------------------------------------------------------------------------

h(x)=\dfrac{1}{3}|x-6|+4

Put the values of x to the equation of the function h(x):

x=-3\to h(-3)=\dfrac{1}{3}|-3-6|+4=\dfrac{1}{3}|-9|+4=\dfrac{1}{3}(9)+4=3+4=7\\\\x=-2\to h(-2)=\dfrac{1}{3}|-2-6|+4=\dfrac{1}{3}|-8|+4=\dfrac{1}{3}(8)+4=\dfrac{8}{3}+\dfrac{12}{3}=\dfrac{20}{3}\\\\x=0\to h(0)=\dfrac{1}{3}|0-6|+4=\dfrac{1}{3}|-6|+4=\dfrac{1}{3}(6)+4=2+4=6


6 0
3 years ago
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