The kite is symmetric about line segment BD.
Therefore
AB = BC
3x + 1 = 22
3x = 22 - 1 = 21
x = 21/3 = 7
Similarly,
AD = CD by symmetry
Therefore
4x = CD
4*7 = CD
28 = CD, the required line segment
Answer: 28
Answer:
3x + y = -5
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Distributive Property
- Equality Properties
<u>Algebra I</u>
Standard Form: Ax + By = C
Point-Slope Form: y - y₁ = m(x - x₁)
- x₁ - x coordinate
- y₁ - y coordinate
- m - slope
Step-by-step explanation:
<u>Step 1: Define</u>
[PS] y - 11 = 3(x - 2)
<u>Step 2: Rewrite</u>
<em>Find Standard Form</em>
- Distribute 3: y - 11 = 3x - 6
- Subtract 3x on both sides: -3x - y - 11 = -6
- Add 11 to both sides: -3x - y = 5
- Factor -1: -1(3x + y) = 5
- Divide -1 on both sides: 3x + y = -5
Answer:
a) 0.3277
b) 0.0128
Step-by-step explanation:
We are given the following information in the question:
N(2750, 560).
Mean, μ = 2750
Standard Deviation, σ = 560
We are given that the distribution of distribution of birth weights is a bell shaped distribution that is a normal distribution.
Formula:

a) P (less than 2500 grams)
P(x < 2500)

Calculation the value from standard normal z table, we have,

b) P ((less than 1500 grams)
P(x < 1500)

Calculation the value from standard normal z table, we have,

2 + 7 - 9 + 11
= 9 - 9 + 11
= 0+ 11
= 11
hope it's helpful !
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