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Zina [86]
3 years ago
11

Write the equation of the line graphed below in Point-Slope form. Use the point labeled on the graph. State the slope and point.

Mathematics
1 answer:
saw5 [17]3 years ago
6 0

Given:

The graph of a line.

To find:

The point-slope form of the given line.

Solution:

From the given graph it is clear that the line passes through the point (1,5) and (0,-1). So, the slope of the line is:

m=\dfrac{y_2-y_1}{x_2-x_1}

m=\dfrac{-1-5}{0-1}

m=\dfrac{-6}{-1}

m=6

The slope of the line is 6 and it passes through the point (1,5). So, the point slope form of the line is:

y-y_1=m(x-x_1)

y-5=6(x-1)

Therefore, the point-slope form is y-5=6(x-1), slope is 6 and the point is (1,5).

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In each diagram, abc is a straight line. Find the unknown angles.
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Answer:

The value of ∠b = 180°

Step-by-step explanation:

Given that;

ABC is a straight line

Another angle is 137°

Find:

The value of ∠a

The value of ∠b

Computation:

We know that, ABC is a straight line

So,

137 + The value of ∠a = 180

The value of ∠a = 180 - 137

The value of ∠a = 43°

The value of ∠b = 360 - 137 - The value of ∠a

The value of ∠b = 360 - 137 - 43

The value of ∠b = 180°

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<span>Which expression is equivalent to 1/4(2−5x+6) ? 

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3 years ago
( EXTRA POINTS PLEASE HELP ) you have a square that measures 5 cm as you have a triangle that has a base of 5 cm and a height of
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Step-by-step explanation:

{5}^{2}  +  \frac{5 \times 8}{2}  =  \\  = 25 + 20 =  \\  = 45

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What is the length of the unknown side of the right triangle?
DerKrebs [107]

Answer:

13

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean Theorem

a^2+b^2=c^2

where<em> a</em> and <em>b</em> are the legs and <em>c</em> is the hypotenuse.

We know that the legs are 5 and 12. We also know the hypotenuse is x, or unknown.

Substitute 5 in for <em>a</em>, 12 for <em>b, </em>and x for <em>c.</em>

<em />5^2+12^2=x^2<em />

Evaluate the exponents.

5^2 is the same as 5*5, which is 25.

12^2 is the same as 12*12, which is 144.

25+144=x^2

Add 25 and 144

169=x^2

We are trying to find out what <em>x</em> is. In order to do this, we have to get <em>x</em> alone. Since x is being squared, take the square root of both sides. The exponent and square root will cancel, leaving x by itself.

\sqrt{169} =\sqrt{x^2} \\\\\sqrt{169}=x\\13=x

The hypotenuse is 13.

4 0
2 years ago
Read 2 more answers
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