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Novay_Z [31]
3 years ago
7

What types of solutions does 6x^2 - 20x + 1 have?​

Mathematics
1 answer:
elena55 [62]3 years ago
3 0

Answer:

2 real solutions

Step-by-step explanation:

We can use the determinant, which says that for a quadratic of the form ax² + bx + c, we can determine what kind of solutions it has by looking at the determinant of the form:

b² - 4ac

If b² - 4ac > 0, then there are 2 real solutions. If b² - 4ac = 0, then there is 1 real solution. If b² - 4ac < 0, then there are 2 imaginary solutions.

Here, a = 6, b = -20, and c = 1. So, plug these into the determinant formula:

b² - 4ac

(-20)² - 4 * 6 * 1 = 400 - 24 = 376

Since 376 is clearly greater than 0, we know this quadratic has 2 real solutions.

<em>~ an aesthetics lover</em>

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a metal strip 42 inches long is to be cut in two pieces. The smaller piece is to be 3 inches more inches than half of the larger
lara31 [8.8K]

Answer:

Piece 1 = 26 inches

Piece 2 = 16 inches

Step-by-step explanation:

42 inches long

Divided into two pieces

Piece 1: x

Piece 2: 0.5x + 3

Add the pieces together and set equal to 42, (or the total)

x + 0.5x + 3 = 42

1.5x + 3 = 42

Subtract 3 from both sides of the equation

1.5x = 39

Divide both sides of the equation by 1.5

x = 26

Piece 1 = 26 inches

Piece 2 = 42 - 26 = 16 inches

Hope this helps :)

7 0
4 years ago
Rectangle JKLM:J(-3, 8), K(-3,-1), L(4, -1),
Maslowich

Answer:

The perimeter of the Rectangle JKLM is 32 unit.

Step-by-step explanation:

Consider the provided coordinates.

Rectangle JKLM: J(-3, 8), K(-3,-1), L(4, -1),  M(4,8)

First plot the points as shown in figure:

The required figure is shown below:

Now find the distance between JK by using the distance formula.

d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

d=\sqrt{\left(-3-\left(-3\right)\right)^2+\left(-1-8\right)^2}=9

Therefore, the length of JK is 9 unit.

Now find the length of the side JM

d=\sqrt{\left(4-\left(-3\right)\right)^2+\left(8-8\right)^2}=7

Therefore, the length of JM is 7 unit.

The perimeter of rectangle is: P=2(l+b)

Therefore,

P=2(7+9)

P=2(16)

P=32

Hence, the perimeter of the Rectangle JKLM is 32 unit.

4 0
4 years ago
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The factors that are needed to be controlled are :
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3 years ago
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Answer:

-120-x

Step-by-step explanation:

Given:

\displaystyle \large{|120+x| \quad (x < -120)}

This is the same as previous one. Recall modulus property:

\displaystyle \large{|a+x| = \begin{cases} a+x \quad (x \geq  -a) \\ -a-x \quad (x < -a) \end{cases}}

Keep in mind that |x+a| and |a+x| are equal via addition property.

Since the question gives interval of x < -120:

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