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Fiesta28 [93]
3 years ago
14

Which statement is true?

Mathematics
1 answer:
Archy [21]3 years ago
7 0

Answer:

B? come at me if im wrong

Step-by-step explanation:

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Uhm help please no links -^-
devlian [24]

Answer:

<u>x = 58</u>

Step-by-step explanation:

180 - 148 = 32

32 + 90 + x = 180

122 + x = 180

180 - 122 = x

x = 58

Have a nice day!

6 0
2 years ago
Read 2 more answers
Find the value of 7!?
Schach [20]
The question isn’t clear, post the question so I could help :) !
5 0
3 years ago
Read 2 more answers
How are &lt;8 and &lt;4 related
Tasya [4]

Answer:

8 divided by 2 is 4

Step-by-step explanation:

U divide 8 from 2

3 0
3 years ago
Help pls fast and give me the steps<br> -15a-19-35=-84
Nimfa-mama [501]

Answer:

a=2

Step-by-step explanation:

-15a-19-35=-84

-15a-19=-49

-15a=-30

a=2

8 0
3 years ago
A new phone costs $230 and the sales tax rate is 7%. What is the total cost of the camera after tax?
rosijanka [135]

That's a question about percentage.

One way to represent percentage is using decimal number. In this way, 1 is equivalent to 100% and the other less percentages using numbers between 0 and 1.

Examples:

  • 90% is equivalent to 0,90.
  • 5% is equivalent to 0.05. It's not 0.5 because 0.5 is equivalent to 50%.
  • 13.17% is equivalent to 0.1317.
  • 245% is equivalent to 2.45.

If we want to know the percentage of a number, we should multiplacate the number by the porcentage in the decimal number form.

Examples:

  • 55.90% of 200 is equal to: 200 \times 0.5590 = 111.8
  • 360% of 88 is equal to: 88\times 3.6 = 316.8

In our problem, we have a phone with a increase of 7%. To solve that, it's important to perceive that $230 is equal to 100% and with a increase of 7%, we will pay 107%.

107% in the decimal number form is 1.07. With that information, we should multiplicate 1.07 by the original value and we will find the answer.

We know that 230\times 1.07 = 246.1, therefore, the total cost of the phone after tax is $246.1.

I hope I've helped. :D

Enjoy your studies. \o/

4 0
3 years ago
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